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19. In the eukaryotic gene shown below, P = promoter, black boxes indicate exons and white boxes with stars (*) indicate intr17. Below is part of one of the strands of DNA being replicated with a primer already in place. 5-AGGTAGACGAACTCGGAG-3 CUGC

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19. The segments c,e,g and i i.e., the exons will be included in the final mRNA.

Introns and exons are nucleotide sequences within a gene. Introns are removed by RNA splicing as RNA matures, meaning that they are not expressed in the final messenger RNA (mRNA) product, while exons go on to be covalently bonded to one another in order to create mature mRNA.

Not only do the introns not carry information to build a protein, they actually have to be removed in order for the mRNA to encode a protein with the right sequence. If the spliceosome fails to remove an intron, an mRNA with extra "junk" in it will be made, and a wrong protein will get produced during translation.Exons TTTTTTTTTTTTTT A AAA 3 -Introns ed splicing s! G AAAA 3 Mature mRNA

17. T

The first nucleeotide DNA polymerase will add is 'T'.

The synthesis always occur in 5' -3' direction (New strand is synthesised in 5'-3' direction so replication start at the 3, end of the existing DNA strand. Here the larger strand is DNA strand and the small uniit if primer.Here the primer is already attached to a position .So the next nuleotide attaches next to the primer .Here the next nucleotide in DNA is 'A' so it's complimentary nucleotide is 'T'. Hence the answer is 'T'À GGTAGAQCGAA CTCGGAG- 3 I CU GCUUGAT Shopping Shui e Synthes ng Entrance Exam

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