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A diseased father and a healthy mother have four kids -> two healthy sons and two...

A diseased father and a healthy mother have four kids -> two healthy sons and two diseased daughters. You know that the disease is X-linked. Answer the following questions: a) is the disease dominant or recessive? b) write genotypes of parents and all possible kids (make a cross)... c) what is the chance for parents to have a diseased son?

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Answer #1

a) it's X linked dominant inheritance.D dominant inheritance occurs When an abnormal gene from one parent causes disease even though the matching gene from other parent is normal and the abnormal gene dominates.

b)the genotypes of the parents and all possible kids can be drawn by punnet square.

... Моке, - x x 37 xx xx. thera de y xy lay G G XD - Diseased allele since it is x in father linked.

C) there is zero chance for son to be diseased as seen from above punnet square. Thank you.

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