Question

1. Total leaf conductance was measured on two plants. One plant was in Los Angeles where the air temperature was 36 °C and relative humidity was 30%. The other plant was in Miami at an air temperature of 36 ° C and a relative humidity of 85%. If the leaf temperature was 38 ° C and if total leaf conductance was 400 mmol m-2 s-1, and assuming standard atmospheric pressure at sea level, calculate the transpiration rates (in units of mmol m-2 s-1) for the leaves of both plants. Show your calculations.

Assume that the plant in Los Angeles is moved to Death Valley and that total leaf conductance remains the same. The air temperature in Death Valley is 46 ° C and the relative humidity is only 5%. If the leaf temperature is 44 ° C, what is the transpiration rate assuming standard atmospheric pressure at sea level? Show your calculations.

Answer 1

AnswERA LA, tempesa tode Plant was in one Relativel homidity 30%. 36°C plant miami temperature 360 other plant RH-85). Cea F Lea tempesa Tuce 38°C total Conduct ance - 400 mmol mrz S-1 standard atmospheric preasure at sea level Transpiration xate (mmol mers-1 for Leaves bom plauth, a E: V PP *glea F Traus piration VPPE Va por persode deficit gleaf Conductance UPDF es ca Leaf OF watej pizessore vapor es = Saturation Foibm e CC 19.277)/(+237.3))

1 le base 10 naToral logarithm). potecrose ses (RM100) wapor Caractual R = reative honidity (1) Plout los Angeles, api Plant miame = P2 rate ResouTion: Transparansion OF PIRE E, EVPDX gleaf fi= (es-ea) x 400 mmol me s~) £1 = [Conbile CC14-27*38)/678 + 237•3]]]- C 17.27 8) 1.028+ 237.3))) x (3 во x ҷоо үтто мне - 1 (o.bile 61 = [Coublie ( 2–38)) -(6.617 e.C2=88) (0-2)] M-2 5-1 x 400 mmol E1= [co.611 X6.47) -6.611 *8,47 x(010)] S- M2 400mmod wide -25 Ei=[3.95 -(3195 x Cors)} x 400

667) m-2 S2 €1= (3.95.-1.18 ] x 400 mmol Eir 1108 mmol mass-1 (you can notica P2 = Er rate OF a Transpiration That the only thing that changes in the same Calwlation onsil The So it' that part ) Eqov pox Sleaf 237.3)) €2= (es-ea) x 400 mmol mersal £2 = [Coublle (C19.27X 16)/68 + 2 6.b 11e (417.27 * 30)) (38 + 237.2]) *cesy 100)] X400 - 5-1 vmed a +2 [3.75 -[3.95 X60.85)] x 400 misol mną mmal ming/ E2237 RH = 59. Dow T~ 44° So ER 3

Ex= [Couble el ( 17,29*44) 164+237.3])) - Co.biz é [(17.27X44)/(447237-3)) x6 (100)]x S-> 400 mnmode fy=[4.49- (es. ciq X 0.05)) x 400 nimel mie S-1 E3=1706. 2 wind in is-

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