Question

YOU MUST ANSWER THE FOLLOWING QUESTIONS ON YOUR OWN PRIOR TO CLASS REVIEW! 1. Label the path of electrons through the light reactions of photosynthesis using the illustration below. A. Include PSII and PSI and label all the complexes involved i. Which complex pushes H* across the membrane? ii. Where do these electrons end up? iii. What is the purpose of splitting H2O? iv. Where do the light reactions take place? 2H2D Ot ENR NAOD ADP photolyetemi photosyetemi wlochtone be- f comples Perleden NADP reductale ATP sunthare

Answer 1

1) A i) b6f6 complex of PSII is throw H+ from stroma to matrix as electron flow through the PSII during light reaction

ii) electron ends up when it's reached to NADPH reductase enzyme which convert NADP+ + H+ + 2e- to NADPH

iii) spliting of water serve two purpose as it is only source of oxygen and other it produce e- which pass to down hill to release energy and also H+ in matrix.

iv) light reaction take place at both PSI and PSII located on outer face of thylakoid membrane and stromal lamella.

2) A. As NADH oxidized in matrix and electron flows through electron transport chain, H+ ion which is formed by oxidation of NADH in matrix will be thrown outside through NADH oxidoreductase or cytochrome complex I to intermembrane space. Through complex I 4 H+ can be pumped outside toward intermembrane space.

Similarly next is complex III which also through 4 H+ from matrix to intermembrane space and lastly by complex no. IV which throw 2 H + from matrix to intermembrane space.

Similarly when FADH2 oxidized in matrix of mitochondria then again electron pass from complex no.II then to complex no. III and then IV as electron pass through these complex which is part of electron tranpart chain, releases energy which is conserve by passing electron from matrix to intermembrane space. In case of FADH2 H+ pass through complex no.III and complex no. IV.

B) see the drown image below

C)FADH2 releases less amount of energy as it able to through less amount of proton from matrix to intermembrane space i.e through only complex no.III and complex IV so total 4+2 = 6 H+

While NADH cause release of total 10H+ as electron pass through complex no. I then complex no. III and then complex IV so total 4+4+2= 10 H+

Now the same proton which is thrown from matric to intermembrane space will diffuse back to matrix but through ATP synthase which produce ATP so more energy formed by NADH as thrown more H+ compare to FADH2

D) product is ATP

3)

	Glycolysis	TCA	oxidative phosphrylation
Input	glucose,ADP,pi	acetyl coA,ADP,pi,NAD+,FAD+	NADH,FADH2,ADP,Pi
Output	pyruvate,ATP,NADH	NADH, FADH2,ATP,O2	ATP,H2O

4)

Mitochondria	chloroplast
Produces ATP from NADH, FADH2 Produces water and utilised oxygen Convert organic substances to inorganic substances Involved in respiration Present at both green and non green area of plant	produces ATP and NADPH from light Produces oxygen and utilised water Produces organic substances from inorganic substances Involved in photosynthesis Present in green area of plant

So presence of both organelle depends on each other for the functional

5) No this synthetic system will not produced ATP under given condition as H + can be pump inside in presence of light but orientation of ATP synthase is wrong it's subunit should be toward outside not inside.

Intermembrane Spale 244 44 1 matrix HA NADHd 447 440 Nant+ht te complex I complex in complet

Hope it's clear..thanks