Homework Answers
Given Black ( B) is dominant obver orange ( b )
and solid colour ( S ) is dominant over spotted (s )
CASE 1
CROSS
Parents - Phenotype Black spotted ( homozygous) x black solid ( heterozygous )
- Genotype BBss x BbSs
Gametes Bs BS, Bs, bS, bs
Punett Square :
| BS | Bs | bS | bs | |
| Bs | BBSs | BBss | BbSs | Bbss |
| black solid | black spotted | black solid | black spotted |
Hence 50% chance for Black spotted.
CASE 2
As heterozygous black is not given solid or spotted colour it can have genotypes BbSs/ Bbss/ BbSS
if we take Bbss then, the obtained progenies are all black spotted i.e, 100%
| Bs | bs | |
| Bs | BBss - black spotted | Bbss- black spotted |
CASE 3
If we take BbSS then , the obtained progenies are all black solid i.e, 0 % to obtain black spotted
| BS | bS | |
| Bs | BBSs- black solid | BbSs- black solid |
Add Answer to:
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