Question

Question 4 5/5 pts Determine the outcome expected from a two point test cross (AaBb x aabb) under the given conditions. Correct! independent assortment 25 AB, 25 Ab, 25 aB, 25 ab , Correct! Completely linked genes with the dihybrid in trans O AB, 50 Ab, 50 aB, 0 ab Correct! Completely linked genes with the dihybrid in cis 50 AB, 0 Ab, 0 aB, 50 ab Correct! Linked, 32 map units apart, dihybrid in trans 16 AB, 34 Ab, 34 aB, 16 ab 4 Correct! Linked, 32 map units apart, dihybrid in cis 34 AB, 16 Ab, 16 aB, 34 ab

explain

Answer 1

Answer4)

In independent assortment, there is found proper segregtion of each allele during gametes formation. Thats why there are found eausl proprtion of each progeny type. 50 of each type progeny is obtained. That's why given answer is correct.

------

The genes are completely linked. This suggests thaylt genes are found in close vicinity to each other. And such genes are in trans conditions. It means genotype of heterozygous parent is Ab/ aB. Thats why there is found only two gametes Ab and aB. And their fusion occurs with ab gamete from double mutant parent and give the Ab/ab 50: aB/ ab 50.

----

In this case, genes are completely linked and are in cis conditions. The heterozygous parent genotype is AB/ ab. Thats why there is found only two gametes AB and ab. And their fusion occurs with ab gamete from double mutant parent and give the AB/ab 50: ab/ ab 50.

----

The genetic distance between two genes is 32 map unigs and dihybrid are in trans conditions. The Genotype of parent in heterozygous conditions is Ab/aB. There is found recombination percentage of 32%. This tells that the recombinat gametes produced by the heterozygous parent is 32% and the parental gametes are 100-32= 68. That's why the recombinat gametes are AB (16) and ab (16)

The parental gametes are Ab (34) and aB (34).

Now the fusion of gametes occurs with ab gamete of ab/ab parent.

That's why the given answer is correct.

----

Here the genes are completely linked and in cis conditions. The heterozygous genotype is AB/ ab.That's why the recombinat gametes are Ab (16) and ab (16)

The parental gametes are AB (34) and ab (34).

Now the fusion of gametes occurs with ab gamete of ab/ab parent.

That's why the given answer is correct.