Question

Question 4 0/1 pts To answer this question it may be useful to draw a diagram. If 89,446 molecules of NAD+ were reduced during all the reactions of cellular respiration, how many molecules of glucose would have been oxidized? Round your answer to the nearest integer. If one glucose oxidized results in 10 NAD being reduced to NADH, how many glucose are required to reduce 100 NAD? Question 5 0/1 pts To answer this question it may be useful to draw a diagram. If, during only the reactions of glycolysis, 94,661 molecules of NADH were produced, how many molecules of pyruvate would be made? Think about what happens with one molecule of glucose: two NADH are made and two pyruvate are made. The number of pyruvate is the same as the number of NADH per glucose.

Answer 1

Ans 4) It is given that when one glucose molecule is oxidized,it will result in 10NAD⁺ being reduced to NADH.

Thus, 10 glucose molecules will be required to reduce 100NAD⁺.

To reduce 89,446 NAD⁺, We will do simple cross-multiplication

1glucose molecule = 10 NAD⁺

"x"glucose molecules = 89,446 NAD⁺

Thus, 89,446 x 1 = 10 x "x"

Or "x" = 89446/10 = 8944.6 or ~8945 glucose molecules.

Ans 5) It is given that 1 glucose molecule produce 2NADH and 2 Pyruvate molecules .

Thus, when 94,661 molecules of NADH are produced, the same number of molecules i.e 94,661 molecules of Pyruvate will be produced.