Why is it smart to transform genes from a liverwort to a moss (Physcomitrella patens) with homologous recombination?
Liverworts are considered to be a key group to understand the genetic basis of the critical innovations that allowed green plants to evolve from an aquatic ancestor and to adapt to the terrestrial environment.
Gene targeting mediated by homologous recombination is a powerful tool for functional analysis by reverse genetics. P. patens is the first moss to be successfully transformed from liverworts and has recently been singled-out as the first land-plant, and perhaps more interestingly the first multicellular eukaryote, in which gene targeting occurs with an highest efficiency.P. patens is one of a few known multicellular organisms with highly efficient homologous recombination meaning that an exogenous DNA sequence can be targeted to a specific genomic position to create knockout mosses. This approach is called reverse genetics and it is a powerful and sensitive tool to study the function of genes.The genome sequence of P. patens has revealed the presence of numerous genes that encode proteins necessary for repair of DNA damages by homologous recombination and by other pathways. Includes PpRAD51, a protein at the core of the homologous recombination repair reaction, is required to preserve genome integrity in P. patens. Loss of PpRAD51 causes marked hypersensitivity to the double-strand break-inducing agent bleomycin, indicating that homologous recombination needs repair reaction
Why is it smart to transform genes from a liverwort to a moss (Physcomitrella patens) with...
Question 6 (1 point) Homologous recombination in yeast facilitates the segregation of genes during meiosis. O the targeted replacement of a gene in a living yeast cell. O the amplification of homologous yeast genes. the independent assortment of separate gene alleles. the expression of similar gene sequences via one promoter.
1. 2. 13. Which statement explains why the recombination frequency between two genes is always less than 50%? Recombination cannot be more than 50% because chromosomes are only 50 map units in length. The genotype of the F, gametes will always be 50% parental gametes and 50% recombinant gametes. Genes with a recombination frequency near 50% are unlinked and have an equal likelihood of being inherited together or separately. F1 gametes always have 50% of their alleles from each parental...
Linked genes segregate independently from each another. are on the same DNA molecule. are genes that affect the same trait. are alleles at the same locus. cannot be mixed by crossing over or recombination
Which of these statements is incorrect? Syntenic genes are located on the same chromosome. Independent assortment results in recombinant chromosomes. You can reliably predict the relative genetic distance from genes’ physical distance on a chromosome. Linked genes are always syntenic. What is the relative genetic distance between two linked genes if the recombination frequency is 0.49? 0.49 cM 4.9 cM 49 cM 490 cM What statement best explains the distortion in Mendelian ratios observed by Bateson & Punnett in 1905?...
You see a recombination frequency of 50% between two genes. Which of the following possibilities can you exclude? That the genes are located close together on the same chromosome That the genes are on different chromosomes O That the genes are assorting independently That the genes are located on the same chromosome, but very far apart Meiosis contributes to genetic diversity by: o Reducing the number of chromosomes for karyogamy (fusion of nuclei) with another gamete O Recombining homologous chromosomes...
For the following please select the correct answer and explain why that answer is correct. 1)The uptake of free DNA from the environment ________, while transfer of DNA with cell-to-cell contact would most likely result in ________. a) transformation / conjugation b)conjugation / transformation c) transformation / transduction 2) A deleterious mutation in recA results in: a) a decrease in homologous recombination. b) an increase in homologous recombination. c) no change in either general or specific recombination.
3. In a series of mapping experiments, the recombination frequencies for four different linked genes of Drosophila were determined as shown in the figure below. Wildtype (dominant) is flat wings, medium leg length, brown abdomen, and medium bristle length. w curled wings 1 short legs a - red abdomen b long bristles g23 O a 12 11 0 b 20 3 8 0 w a b The numbers in the boxes are the recombinatior frequencies in between the genes (in...
Explain why smart devices are desirable and give two examples of how businesses could benefit from smart devices.
The stocks growing from the moss below represent what stage of the moss life cycle? gamete formation sporophyte gametophyte union of the algae and fungus nutrient procurment
Why does moss have an association with cyanobacteria. is it like symbiosis, or? Also, can you reference sources