Question

please show all work for 2 & 3

2. Given the following data, what is the recombination frequency? Select an answer below and show how you made your calculaton. Phenotype Progeny from test cross 46 44 Red, long Yellow, oval Red, oval Yellow, long Total a) 45% b) 5% c) 10% d) 90% 3. The genes dumpy (dp), clot (cl), and apterous (ap) are linked on chromosome II of Drosophila. In a series of two-point mapping crosses, the following genetic distances were determined. What is the sequence of the three genes? (Make a diagram showing the order and distances.) dp-ap 42 dp-cl ap-cl 39

Answer 1

2) Recombination requny - Total number of recombinants / Total area . x 100% - Red long 46. nd yellow oval 44 both are parintal type and recombinants are red oval 58 yellow long 5. Thus combination. 575 Irequery will be =- -X100% 46+44+5+5 x100. - 10 = 10% rt fo he u Answer is c' 13) Given that old ez lous jo matology dp- ap 42 dp- d 3 ap-d 39. top We know that genetic distances are generated from recombination Freqenies. If the frequeny of higher then, the genetic distances will be nicher This means that if they are located at two far Ends of chromosomes, they would get separated during the crossing ovce)

Acording to the data. up and ap are located very far fome each other which is 42 units. ap and cl are also located very for which i - 39 units. el reglur Both of them are very far from ap gene. But dp and el are very close to each other So, the genetic map will be Det mellan de moda — 39 ap. please rate my Answer