Question

Biochemistry

3. Question a. In part B, the reactions were performed with 5.0 mM galactose. This value could be expressed in a quantity instead of using a concentration (as was done with ONPG: milligrams provided instead of a concentration). If the goal is to replace the concentration of galactose with a mass of galactose, what would that mass be?

Answer 1

if have not given the volume of solution but

Molecular weight of - 180. 156 galactose ore 1 prolar solution wreans, the solution contain 1 mole of galactose in 1 ritse of solution. - 1 molar solution & Litse) contain 180.156 s n . llitere) will contain = 120.156xs gran s man in (ritre) will contain - 180.156 x 5 1680 1 mrga sola = 0.900 gen 2.94 1000 mg - goo mg.

I have given answer for 1 litre volume.

1 litre 5mM galactose solution will contain 900 mg of galactose.

If you make less volume if have to divide the amount of galactose by that factor.

As you make 5 mM 500 ml solution then 900/2= 450 mg of galactose will be needed.