Question

1. You carry out a dihybrid cross in petunias. You are unaware of the linkage relationship between the genes DBL and CAS. One

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

a).

D= Double; d = Single

Cascading = C; Upright = c

CD/cd (F1) x (tester) cd/cd ---parents

b).

i). If unlinked:

cd

CD

CD/cd (cascading, double)—25%

cd

cd/cd (upright, single)---25%

Cd

Cd/cd (cascading, single)—25%

cD

cD/cd (upright, double)—25%

ii).

If completely linked:

cd

CD

CD/cd (cascading, double)—50%

cd

cd/cd (upright, single)---50%

iii).

Distance between genes (mu) = Recombination frequency (%)

CD/cd genotype produces 4 types of gametes as below:

Recombinant gametes (30%):

Cd = 15%

cD = 15%

Non-recombinant gametes (70%):

CD = 35%

cd = 35%

cd/cd genotype produces only one type of gametes, cd.

Cd

CD (35%)

CD/cd (cascading, double)—35%

cd (35%)

cd/cd (upright, single)---35%

Cd (15%)

Cd/cd (cascading, single)—15%

cD (15%)

cD/cd (upright, double)—15%

c).

CD/cd genotype produces 4 types of gametes as below:

Recombinant gametes (20%):

Cd = 10%

cD = 10%

Non-recombinant gametes (80%):

CD = 40%

cd = 40%

cd/cd genotype produces only one type of gametes, cd.

Cd

CD (40%)

CD/cd (cascading, double)—40%

cd (40%)

cd/cd (upright, single)---40%

Cd (10%)

Cd/cd (cascading, single)—10%

cD (10%)

cD/cd (upright, double)—10%

Number of single flowering, cascading growth habit = 10/100 * 360 = 36

Add a comment
Know the answer?
Add Answer to:
1. You carry out a dihybrid cross in petunias. You are unaware of the linkage relationship...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2. You carry out a dihybrid cross in sweet peas where you examine the flower color...

    2. You carry out a dihybrid cross in sweet peas where you examine the flower color locus (use symbols based on "P" for this gene) and blooming time locus (use symbols based on "L" for this gene). You cross a true breeding purple- flowering, early blooming plant to a true breeding red-flowering, late blooming plant. The F1 plants are all purple- flowering and late blooming. The F1 plants were subsequently used in a testcross. The flower color locus and the...

  • 5. You started working in a Drospohila lab. You are studying two different autosomal traits, body...

    5. You started working in a Drospohila lab. You are studying two different autosomal traits, body color and antennae length. Gray body (B) is completely dominant to black body (b) and long antennae length (A) is completely dominant to short antennae length (a). You cross true-breeding gray bodied, long antennae files to true-breeding black bodied, short antennae. The F1 progeny all have gray bodies and long antennae. a. You perform a testcross to the F1 progeny produced from the parent...

  • 1. A genetic cross in which the inheritance of two traits is observed is called a...

    1. A genetic cross in which the inheritance of two traits is observed is called a A) Dihybrid cross. B) Monohybrid cross C) Backeross D) Testcross 2. For single crossovers, the frequency of recombinant gametes is half the frequency of crossing over because A) A testeross between a homozygous and heterozygote produces 1/2 heterozygous and 1/2 homozygous progeny. B) The frequency of recombination is always 50%. C) Each crossover takes place between only two of the four chromatids of a...

  • 1. In a cross between two pure-breeding varieties of radish, one with red and the other...

    1. In a cross between two pure-breeding varieties of radish, one with red and the other with white roots, all the F1 progeny had purple roots. The F2 obtained by selfing the F1 segregated as follows: Red Purple 80222 White 98 Two models (A and B) were suggested to account for these results:- A) Root colour is controlled by a single gene with two alleles showing incomplete dominance B) Root colour is controlled by two unlinked genes showing (recessive) epistasis....

  • Fun-filled Genetics activity Set Psa plants were particularly well suited for use in Mendel's breeding experiments...

    Fun-filled Genetics activity Set Psa plants were particularly well suited for use in Mendel's breeding experiments for all of the following m e thal Al was show easily terved various in a number of characters, such as a shape and flower color, it is powible to completely control tingshotween different pe plants, it is possible to a large numbers of progeny from any given cross. Dipeas have unusually long generation time, many of the observable characters that vary in pea...

  • Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in...

    Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...

  • **Please answer ALL 10 QUESTION** 1. A species of flowering plant includes plants with blooms that...

    **Please answer ALL 10 QUESTION** 1. A species of flowering plant includes plants with blooms that range from bright golden yellow to very pale yellow; no flowers carrying the yellow pigment allele appear white. The allele for yellow flower color: a. must be a suppressor of another allele. b. demonstrates incomplete penetrance. c. demonstrates variable expressivity. d. must be a modifier of another allele. e. demonstrates variable penetrance. 2. Coat color in mice is determined by two alleles acting at...

  • 2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving...

    2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving rise to a “hairless” phenotype. In the homozygous condition, H is lethal. An independently assorting dominant allele S has no effect on bristle number except in the presence of H, in which case a single dose of S suppresses the hairless phenotype, thus restoring the "hairy" phenotype. However, S also is lethal in the homozygous (S/S) condition. What ratio of hairy to hairless flies...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT