Question
1 e and 2 e 1 need help on those. ive posted this multiple times and peolle have anawered . but both times i posted they have given me two diff reaponses for the answers. please help for 1e and 2e. if u coild look at the chart and decide the sequences for me

please be simple and clear

3rd base in codon puco sucopucobuco 2nd base in codon CAIG SS2288 222222233&a The Genetic Code 1st base in codon
Norma Gonzalez2 Transcripcion Translation Homework 1. The order of bases on the template strand of DNA a geme is AATACCTTGCAA
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Answer #1
  • The genetic information in the fragment of DNA or a gene, may be expressed by its ability to encode a specific RNA or protein.
  • The product thus generated typically “expresses” the genetic information of the gene. As described by the hypothesis of George Wells Beadle and Edward Lawrie Tatum, “One gene one enzyme”; the product of each genetic expression influences the activity of the cell.
  • Thus the process of transcription occurs to produce mRNA and translation to produce protein is defined as the central dogma.
  • DNA - > mRNA - > Protein
  • 5’ to 3’ strand of DNA serves as coding strand.
  • 3’ to 5’ strand of DNA act as template strand.
  • RNA is synthesized by complementary base pairing with the template strand.
  • Thus, the RNA will have same sequence as coding strand (only T is replaced by U) and is oriented in 5’ to 3’ direction.

1.

For the given sequence:

a. Template strand:

3' AATACCTTGCAA 5'

b. Complementary coding strand (Sense strand):

5' TTATGGAACGTT 3'

c.

mRNA:

Amino acid:

Translation starts from the start codon sequence (AUG) and ends at Stop codons (UAG, UGA, UAA).

5' UUAUG GAA CGU U 3'

Met-Glu-Arg

d.

Original template strand:

3' AATACCTTGCAA 5'

Mutated template strand (first C deleted):

3' AATACTTGCAA 5'

Corresponding coding strand:

5' TTATGAACGTT 3'

Corresponding mRNA:

5' UU AUG AAC GUU 3'

e. Amino acids:

Met- Asn- Val

2.

For the given sequence:

a. Template strand :

3' CCTACGGACGA 5'

b. Complementary coding strand (Sense strand):

5' GGATGCCTGCT 3'

c.

mRNA:

Amino acid:

Translation starts from the start codon sequence (AUG) and ends at Stop codons (UAG, UGA, UAA).

5'GG AUG CCU GCU 3'

Met-Pro-Ala

d.

Original template strand:

3' CCTACGGACGA 5'

Mutated template strand (first G deleted):

3' CCTACGACGA 5'

Corresponding coding strand:

5' GGATGCCTGCT 3'

Corresponding mRNA:

'5'GG AUG CUG CU 3'

e. Amino acids:

Met- Leu

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