Homework Answers
Answer - Because there was clumping of blood after adding antisera to each well.
Explanation
The serological test is performed to determine the blood group and its respective allele. To determine the blood group, the blood is collected from the patient and anti-sera of A and B are added in respective wells. If clumping observed than the individual has that blood group. If clumping observed in A antisera then the blood group is A and it is same for B. if no clumping observed then it is O group. Father 3 is dominant of allele A, B and Rh because it showed clumping of blood after adding antisera A, B and Rh. Hence the dominant allele is A, B and Rh.
Option 2 is not correct because if there is not clumping then it indicates that blood doesn't contain A or B antigen and hence A and B are not dominant allele.
Option 3 is not correct because allele that Andrea has is not only determined by the father but also by the mother.
Option 4 is not correct because if none of the other father has doesn't mean that father 3 should have dominant alleles.
Add Answer to:
Question 5 1.5 pts According to the results shown below, we know that possible father #3...
8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and...
8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and two men Y and Z). The analysis is limited to the ABO and Rh blood group systems. Using the space below, and assuming that only YorZ could be the biological father, assign each child to his/her possible father. You can use either Punnett squares for each trait, or the process of Mother Possible Fathers Children Possible father for each child elimination. There may be...
I did 1-5 but confused on the rest LAB EXERCISE 4.1 continued Name 6 Remember that...
I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
Answer the highlighted questions t should be a crime At 1:00 a.m., someone breaks a window...
Answer the highlighted questions
t should be a crime At 1:00 a.m., someone breaks a window in the back of a store and robs the safe. On the way out, the thief cuts himself (or herself) on a piece of broken glass. You are a forensic detective called to the scene. You test a sample of blood left behind by the thief. It is B+. While you are there, police bring in two suspects, each with a cut forearm, whom...
2 The inheritance of autosomal dominant traits also can be explored through pedigree analysis, Polydactylism, having...
2 The inheritance of autosomal dominant traits also can be explored through pedigree analysis, Polydactylism, having extra digits, results from a dominant gene (P). Using Figure 3.8, explain the appearance of polydactyly in children of generation 3. O IIION FUR 8.8 Polydactylism pedigree. X-linked traits are carried exclusively on the X chromosome. Because a male possesses only one X chromosome, if he receives an X chromosome that carries an X-linked trat he will express that trait. For a female to...
Background INFO There are four types of blood: A, B, AB, and O (Figure 4). Each...
Background INFO
There are four types of blood: A, B, AB, and O (Figure 4). Each
is characterized by the glycoproteins (proteins with a sugar
attached) and lipoproteins (proteins with a lipid attached)
embedded in the surface of red blood cells (RBCs). In addition to
type, blood can be rhesus (Rh) factor positive or negative.
These proteins are inherited and may differ from individual to
individual. If, during a transfusion, an individual receives
blood with the incorrect RBC proteins (for...
Table 2. Results of blood and hemoglobin tests for case study. Subject Blood type (phenotype) Hemoglobin...
Table 2. Results of blood and hemoglobin tests for case
study.
Subject
Blood type (phenotype)
Hemoglobin genotype
Mother
A+
HbAS
Baby
A+
HbAA
Male Subject
O-
HbAS
Based on your results shown in Table 2, can you exclude the
possibility of paternity? Cite the specific results
that allow you to make this claim
What are ALL of the potential genotypes for each subject based
on blood type?
Define the difference between genotype and phenotype.
Supplementary Information A gene is a...
PPPPPP Step 5: Determine the phenotype of cach possible allele combination shown in the offspring. In...
PPPPPP Step 5: Determine the phenotype of cach possible allele combination shown in the offspring. In this instance, three of the offspring Chose with the genotypes EE, Ee, and Be) have free earlobes, because the free earlobe allele is dominant to the attached-carlobe allele. One offspring, ec, has attached earlobes. Therefore, the proba- bility of having offspring with free earlobes is 3/4 and with attached earlobes is 1/4. Additional Single-Factor Inheritance Problems (One Trait Followed from One Generation to the...
I really don't understand number 3 for both questions please and Thanks you chup is called...
I really don't understand number 3 for both
questions
please and Thanks you
chup is called the bleeder's disease because the affected person's blood is unable to clot. nougn hemophiliacs do bleed externally after an iniury they also suffer from internal bleeding pa around joints. Hemorrhages can be checked with transfusions of fresh blood (or plasia U protein. The most common type of hemophilia is hemophilia A, due to the absence or minimal presence of a particular clotting factor called...
Read below article and respond to it Laive opinion)?7 We both know the risk of having...
Read below article and respond to it Laive opinion)?7 We both know the risk of having an abortion, like pelvic infections, blood clots or scar tissue in the uterus, and even an incomplete abortion" (Heisenberg). Although I know, you have said you are not ready to have the responsibility of a young person at this time. I believe you should look at a different option, but of the risk that comes with abortion. We can look at foster care and...
Peter was born after an uneventful pregnancy and weighed 3.1kg. At 3 months, he developed otitis...
Peter was born after an uneventful pregnancy and weighed 3.1kg. At 3 months, he developed otitis media and an upper respiratory tract infection. At the ages of 5 months and 11 months, he was admitted to hospital with Hemophilus influenza pneumonia. The infections responded promptly to the appropriate antibiotics on each occasion. When 16 months old, he had a relapse of otitis media. He is the fourth child of unrelated parents: his three sisters show no predisposition to infection. Examination...
8 A case of disputed paternity involves a woman, her children (1, 2 and 3), and two men Y and Z). The analysis is limited to the ABO and Rh blood group systems. Using the space below, and assuming that only YorZ could be the biological father, assign each child to his/her possible father. You can use either Punnett squares for each trait, or the process of Mother Possible Fathers Children Possible father for each child elimination. There may be...
I did 1-5 but confused on the rest
LAB EXERCISE 4.1 continued Name 6 Remember that the ability to taste PTC is dominant to the inability. Two normally pigmented taster parents have an albino, taster son and a non-taster daughter with normal pigmentation. Using A and Tand a and t for the dominant and recessive alleles, respectively, create a Punnett square for two traits, as shown on pages 71-73 in the section "Transmission of Autosomal Traits: Two at a Time."...
Answer the highlighted questions
t should be a crime At 1:00 a.m., someone breaks a window in the back of a store and robs the safe. On the way out, the thief cuts himself (or herself) on a piece of broken glass. You are a forensic detective called to the scene. You test a sample of blood left behind by the thief. It is B+. While you are there, police bring in two suspects, each with a cut forearm, whom...
2 The inheritance of autosomal dominant traits also can be explored through pedigree analysis, Polydactylism, having extra digits, results from a dominant gene (P). Using Figure 3.8, explain the appearance of polydactyly in children of generation 3. O IIION FUR 8.8 Polydactylism pedigree. X-linked traits are carried exclusively on the X chromosome. Because a male possesses only one X chromosome, if he receives an X chromosome that carries an X-linked trat he will express that trait. For a female to...
Background INFO
There are four types of blood: A, B, AB, and O (Figure 4). Each
is characterized by the glycoproteins (proteins with a sugar
attached) and lipoproteins (proteins with a lipid attached)
embedded in the surface of red blood cells (RBCs). In addition to
type, blood can be rhesus (Rh) factor positive or negative.
These proteins are inherited and may differ from individual to
individual. If, during a transfusion, an individual receives
blood with the incorrect RBC proteins (for...
Table 2. Results of blood and hemoglobin tests for case
study.
Subject
Blood type (phenotype)
Hemoglobin genotype
Mother
A+
HbAS
Baby
A+
HbAA
Male Subject
O-
HbAS
Based on your results shown in Table 2, can you exclude the
possibility of paternity? Cite the specific results
that allow you to make this claim
What are ALL of the potential genotypes for each subject based
on blood type?
Define the difference between genotype and phenotype.
Supplementary Information A gene is a...
PPPPPP Step 5: Determine the phenotype of cach possible allele combination shown in the offspring. In this instance, three of the offspring Chose with the genotypes EE, Ee, and Be) have free earlobes, because the free earlobe allele is dominant to the attached-carlobe allele. One offspring, ec, has attached earlobes. Therefore, the proba- bility of having offspring with free earlobes is 3/4 and with attached earlobes is 1/4. Additional Single-Factor Inheritance Problems (One Trait Followed from One Generation to the...
I really don't understand number 3 for both
questions
please and Thanks you
chup is called the bleeder's disease because the affected person's blood is unable to clot. nougn hemophiliacs do bleed externally after an iniury they also suffer from internal bleeding pa around joints. Hemorrhages can be checked with transfusions of fresh blood (or plasia U protein. The most common type of hemophilia is hemophilia A, due to the absence or minimal presence of a particular clotting factor called...
Read below article and respond to it Laive opinion)?7 We both know the risk of having an abortion, like pelvic infections, blood clots or scar tissue in the uterus, and even an incomplete abortion" (Heisenberg). Although I know, you have said you are not ready to have the responsibility of a young person at this time. I believe you should look at a different option, but of the risk that comes with abortion. We can look at foster care and...
Most questions answered within 3 hours.
-
Please use Logicly!
Create a 4 bit sequential counter that is capable of counting up
or...
asked 32 seconds from now -
I1(t) and I2(t) describe the intensity of two
light waves.
I1(t)= 10sin(30t+π/4)
I2(t)=
10sin(30.4t+π)
Assume that...
asked 4 minutes ago -
A sample of steam with a mass of 0.501 g at a temperature of 100
∘C...
asked 9 minutes ago -
A block sits on the floor. (a) What is the magnitude of the
frictional force on...
asked 10 minutes ago -
state one specific part from disability law such as ADA
(Americans with Disability Acts) or policy...
asked 11 minutes ago -
please simplify how vapor pressure lowering is related to a
rise in the boiling point solution
asked 26 minutes ago -
write a java program that does the following
Part one
Use a For loop to compute...
asked 24 minutes ago -
"A student in another class made a claim that many people are
now talking about outlawing...
asked 25 minutes ago -
Test the hypothesis using P-value approach. Be sure to verify
the requirements of the test.
H0:...
asked 1 hour ago -
For a voltaic cell based on the reaction below, which statement
is correct?
Zn(s)+2H+(aq)→Zn2+(aq)+H2(g)
Zn2+(aq) is...
asked 52 minutes ago -
If 20 g of Na2SO4 is reacted with 20 g of
Al(NO3)3 according to the following...
asked 43 minutes ago -
One difference between periodic and perpetual inventory systems
is:
Multiple Choice Cost of goods sold is...
asked 49 minutes ago