The approximate concentration of the carona polymerase stock will be as follows
The OD 0.6 at an obsorbance of 595nm on the Y axis corresponds to 1mg on the X-axis of BSA std.
Therefore it is assumed that the sample which was studied in the Bradford assay has 1mg/ml of protein. But however an initial dilution was done
where a dilution nof the polymerase sample is done: 50ul with 100ul of water which is has a dilution factor of 3 ((50+100)/50)
so multiply the concentration of the sample which was used to plot in the graph with the dilution factor
1 X 3 = 3mg
Therefore the concentration of the Carona polymerase stock is 3mg/ml
4) You have been given the job of designing an experiment to test the effects of...
I forgot to put down that the observance (=OD) at 280nm is 0.679A Experiment 8: Bradford assay and UV-method for determination of protein concentrations Materials - An ice bucket with ice, your purified sample, three visible plastic cuvettes for Bradford assay, one UV plastic cuvette for UV-method, a piece of parafilm, a Vis-spec, a Lab Quest, Bradford reagent, white tape (share), a sharpie. Bradford assay (reference 21) 1. Add 990 uk Bradford assay reagent to a plastic cuvette 2. Blank...
1. You have generated the following standard curve after a Bradford Assay to measure Absorbance vs samples of known BSA concentrations. Now you need to determine the amount of protein in two mitochondria samples taken from fish, one taken from fish under normal conditions and the other taken from fish under oxidative stress. The absorbance reading for the normal fish fraction was A595=175, and the absorbance reading for the stressed fish fraction was A595= 275 Bradford Assay Standard Curve y...