Homework Answers
According to the condition given in question
we have, two alleles B1 and B2
frequency of allele B1 is 0.72, frequency of allele B2 is 1-0.72 = 0.28.
now in order to find frequency of heterozygotes, we have the formula, 2pq
here p = B1 = 0.72, q = B2 = 0.28.
then frequency of heterozygotes = 2pq = 2B1B2 = 2 x 0.72 x 0.28 = 0.40
Thus the frequency of heterozygote is 0.40
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