Question

Suppose a population of organisms is in Hardy–Weinberg equilibrium with respect to a gene that has two alleles, Y and y. The YY genotype has a frequency of 0.11, the Yy genotype has a frequency of 0.44, and the yy genotype has a frequency of 0.45. Calculate the frequency of each allele to two decimal places.

Y allele frequency:

y allele frequency:

Answer 1

As the population is in Hardy Weinberg equilibrium , so the frequency of both the alleles 'Y' and 'y' can be found using simple equation : p+q=1.

Further explanation is attached here:

Solution : - Conditions : Populertion is in Hardy Weinberg Equilibrium. -Y 1 gove < 7 can be represented by P. so y = can be represented by a Frequency of genotypes: YY = 0.11 (P2) Yy= 0.44 ( pq) * y = 0.45 As we know, - (P+qJ ² = P²+ 2 p q + qe & pr q=1. For frequency of aftele (Y) or P = Joll of the - VT = 3:31 = 0.33 100 p+q=1 If p = 0.33 0.33 + q = 1 q= 1-0.33 = 0.67. the frequency of Y = 0.33 & y = 0.67. So,