Question

4. (25 points) (Show all work) Design an inverter circuit using a NMOS transistor and a resistor with Vout-5.0 when Vin-OV and Vout-0.3 V when Vin-SV with Kn-300uA/V" and a VrN = 1 V. Use ID-Kn(VGS-VTNJVDs. You have a 5V supply available to power the circuit.

Answer 1

Designing of an inverter circuit using NMOS transistor and a resistor: ie we design NMOS resistive load inverter Given Data: K _ N = 300 mue A/V^2 V_TN = 1 V V_out = 5v rightarrow V_in = 0V V-out = 0.3 V rightarrow V_in = 5V We have 5V supply to power the circuit I_D = K_n (V_ GS - V_ TN) V_ DS Circuit diagram: Here two states in inverter i) Triode region V_i = V-H = 5V => V_0 = 0.3V ii) Cut of region V_i = V_L = 0V => V_0 = 5v consider cutoff, V_i = V_L = oV V_i = V_L , V_TN = 1V (V_i < V_TN) I_D = 0V => V_0 = V_H = V_0D = 5V [Therefore because transistor in cutoff region] Note: typically V_L = V_i = 0.2 V \r\n Consider Triode region (V_i = V_H) Given . = K_n (V_GS - V_TN) V_DS