K = 40N/m , total weight W = (5+2)×9.8 = 68.6N
Let compression is y.
Hence from Hook's law, W = ky
=) y = W/k = 68.6/40 = 1.715m
Now after removal of 5kg block, m = 2kg
Applying conservation of energy, U = K
=) 1/2 ky^2 = 1/2 mv^2
=) v = y √k/m = 1.715× √20 = 7.67m/s
=) v = 7.67m/s
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