Homework Answers
Solution)
In triangles
CDF and BDE
We have
Angle DCF= angle DBE (isosceles triangle)
Angle CFD= angle BED (90° as lines are perpendicular)
CD= BD (mid point segments)
Thus triangle CDF is similar to triangle BDE (A.A.S axiom of congruency)
Thus
FD= ED (corresponding sides of congruent triangles)
Which is required to prove hence proved.
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Kindly answer the question neatly. Thanks. In AABC, AB = AC and BC = 6 cm....
Kindly answer the question neatly. Thanks.
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can you please please help me with these proofs R Cand CoDNder the triangle AABC and...
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14. The point D on the hypotenuse BC of the right isosceles AABC is such that BD= AB. Prove that ZBAD = 67.5° baAB = CD, then AD | BC 16 Prove that the sum of the interior angles of a quadrilateral is 360° ADCD tho hieectors of the interior onel
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3
nat you ho has cheated on this exam. 1. Let AABN and AA'B'Y by asymptotic triangles. Prove that if LABN 2 ZA'B'Y and AB> ΑΒ , then /BAΩ< ΒA. 2. Let AABC be an ordinary triangle and let D be any point of the interior. Prove that the sum of the angles of AABD is greater than the sum of the angles of AABC. 3. Suppose that two lines & and m have a common perpendicular MN. Let A...
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Kindly answer the question neatly. Thanks.
In AABC, AB = AC and BC = 6 cm. D is a point on the side AC such that AD = 5 cm and CD = 4 cm. Show that ABCD – AACB and hence find BD.
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