Question

design an active low pass filter with cutoff frequency of 400 hz and gain of 10 db at dc

Answer 1

Given that, cut-off frequency a fe = 400 HZ- DC gain = 10 db Low pass filter circuit, R2 un Ri ofw Vout Til Vin RT For the above figure, é = 1 21T RC ... Now, De gain = 1+ one NOW, - чоо to santec = 400 2 IT RC RC = 21' Kupo KO 21 x 400 fin R = 1kr, S i ca 2T X 400 X 1X10 Toxos a Ic=39.8 MF

Dc gan slo (:: 10 db = 102 **(1+ ) = 10 der R, = 1 kr .R2 = 9KR . To achieve fc = 400 Hz and OC gain of 1008, the low pass (active) used is 9KR Wh . ich WI ovout vann Vin IKS 39.84F

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