Homework Answers
mixture of mass of sand and sodium carbonate = 0.5518g
mass of sand = 0.3208g
mass of sodium carbonate = mixture of mass of sand and sodium carbonate - mass of sand
= 0.5518-0.3208 = 0.231g
The percent sodium carbonate in the original mixture = mass of sodium carbonate*100/mass of original mixture
= 0.231*100/0.5518 = 41.86%
The percent sand in the original mixture = mass of sand*100/mass of original mixture
= 0.3208*100/0.5518 = 58.14%
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