a draw positive and negative and zero B find fault current Ia Ib Ic Question: 03...
The reactance data for the power system shown in figure 10.30 in per unit on a common base is as follows: *************Remember calculations are needed at bus 2 **************** 10.15. The reactance data for the power system shown in Figure 10.30 in per unit on a common base is as follows Item X1 G1 0.10 0.10 0.05 G2 0.10 0.10 0.05 T, 0.25 0.25 0.25 T 0.25 0.25 0.25 Line 1-2 0.30 0.30 0.50 Ti 1 3 2 FIGURE 10.30...
The zero-, positive-, and negative-sequence bus impedance matrices for a three bus power system are given below 5. T0.10 0.15 0.121 Bu0.15 0.10 0.08 pu [0.16 0.10 0.15] Lo.15 0.14 0.30 0.12 0.08 0.35 ZBus ZBus0.10 0.20 0.14 pu Determine the per unit fault current and the bus voltages during fault for (a) A bolted three-phase fault at bus 2. (b) A bolted single line-to-ground fault at bus 2. (c) A bolted line-to-line fault at bus 2 (d) A bolted...
For the network shown below, the pu reactance data are equivalent sequence circuit and calculate the fault current in per unit for a bolted single line- to-ground fault at bus 2. The pre-fault bus voltages are assumed to be 1 pu given in the table. Draw the Ti T2 1 2 3 G1 G2 5 X2 Item G1 0.10 0.10 0.05 0.05 G2 0.10 0.10 0.01 T1 0.01 0.01 0.01 T2 0.01 0.01 Line 2-3 0.10 0.10 0.20 Line 3-5...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
Bus A Bus B R1 T1 line 1 20% 80% line 2 T2 R2 110 kV 11 kV Note TX impedance TX leakage reactance TX zero sequence impedance-TX positive Data 3 phase fault MVA Bus A 1152 MVA Single P-G level Bus A 8k T1 = T2 = 50MVA X1 0.006 RAk TX1 X2 0.0055 Rik TX2 Earthing resistance-R1-R2-2 ohm z+ sequence reactance 55j) ohm for both sequence impedance Source negative impedance -positive sequence impedance Source zero sequence impedance- purely...
The one-line diagram of a simple power system is shown in Figure 1. The neutral of each generator is grounded through a current-limiting reactor of 0.25/3 per unit on a 100-MVA base. The system data expressed in per unit on a common 100-MVA base is tabulated below. The generators are running on no-load at their rated voltage and rated frequency with their emfs in phase. Determine the fault current for the following faults giving Zo = 0.35, Z = 0.22...
The positive, negative and zero sequence bus impedance and admittance matrices of a system are given as follows:\(Z^{+}=Z^{-}=j\left[\begin{array}{ccc}0.14 & 0.11 & 0.125 \\ 0.11 & 0.14 & 0.125 \\ 0.125 & 0.125 & 0.175\end{array}\right] \quad Y^{+}=Y^{-}=j\left[\begin{array}{ccc}-24 & 10 & 10 \\ 10 & -24 & 10 \\ 10 & 10 & -20\end{array}\right]\)\(Z^{0}=j\left[\begin{array}{ccc}0.10 & 0.10 & 0.10 \\ 0.10 & 0.30 & 0.20 \\ 0.10 & 0.20 & 0.30\end{array}\right] \quad Y^{0}=j\left[\begin{array}{ccc}-16.66 & 3.33 & 3.33 \\ 3.33 & -6.66 & 3.33...
Bus A Bus B R1 T1 line 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96) X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
2. A single-line diagram of the power system considered is shown in Figure P2a, where negative- and zero-sequence reactances are also given. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn = 0.05 per unit on the motor base. The per-unit zero-, positive and negative-sequence networks on a 100-MVA is shown in Figure P26, 13.8-kV base in the zone of the generator. a. Reduce the sequence networks to their...