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For the network shown below, the pu reactance data are equivalent sequence circuit and calculate the fault current in p...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fau...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
can you calculating this question and explain why? thanks The ratings and sequence reactances of the components for...
can you calculating this question and explain why?
thanks
The ratings and sequence reactances of the components for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 1/0° per unit (pu). Bus 8 L3 Bus 1 T1 Bus 4 T2 Bus 2 Bus 5 L1 L2 G1 Bus 3 T3 Bus 7 Bus 6 D.6975 Figure Draw the per unit impedance sequence networks and determine the per unit (a) Thevenin impedances of the...
The reactance data for the power system shown in figure 10.30 in per unit on a...
The reactance data for the power system shown in figure 10.30 in
per unit on a common base is as follows:
*************Remember calculations are needed at bus 2
****************
10.15. The reactance data for the power system shown in Figure 10.30 in per unit on a common base is as follows Item X1 G1 0.10 0.10 0.05 G2 0.10 0.10 0.05 T, 0.25 0.25 0.25 T 0.25 0.25 0.25 Line 1-2 0.30 0.30 0.50 Ti 1 3 2 FIGURE 10.30...
The zero-, positive-, and negative-sequence bus impedance matrices for a three bus power system are given...
The zero-, positive-, and negative-sequence bus impedance matrices for a three bus power system are given below 5. T0.10 0.15 0.121 Bu0.15 0.10 0.08 pu [0.16 0.10 0.15] Lo.15 0.14 0.30 0.12 0.08 0.35 ZBus ZBus0.10 0.20 0.14 pu Determine the per unit fault current and the bus voltages during fault for (a) A bolted three-phase fault at bus 2. (b) A bolted single line-to-ground fault at bus 2. (c) A bolted line-to-line fault at bus 2 (d) A bolted...
Power System
A simple three-phase power system is shown in Figure 2. Assume that the ratings of the various devices in this system are as follows: • Generators G1, G2: 40 MVA, 13.2 kV, = 0.15 pu, = 0.15 pu, = 0.08 • Generator G3: 60 MVA, 13.8 kV, = 0.20 pu, 0.20 pu, - 0.08 • Transformers T1, T2, T3, T4: 40 MVA, 13.8/138 kV, X1 = X2 = 0.10 pu, XO 0.08 pu Transformers T5, T6: 30 MVA, 13.8/138 kV, X1 = X2...
Please help me to answer those question and answer with PHASOR MAGNITUDE and PHASE ANGLE Part...
Please help me to answer those question and answer with PHASOR
MAGNITUDE and PHASE ANGLE
Part 1:
Taking the rated power of generator G1 as the base power, and
the transformer T1 low-voltage
side rated voltage as the base voltage, calculate the Thevanin’s
equivalent zero-sequence
impedance, positive sequence impedance and the negative sequence
impedance viewed from
Bus-2. Specify your answers in per-unit.
Part 2:
Assuming the pre-fault bus voltages are at 1.02 pu, calculate the
fault currents in each phase...
Assuming there is a FAULT at BUS 3, Determine the thevenin equivalent of each series network...
Assuming there is a FAULT at BUS 3, Determine the thevenin
equivalent of each series network as viewed from the fault bus.
Given:
-Prefault voltage is 1.0 per unit
-Prefault load currents and delta-wye transformer phase shifts
are neglected
Synchronous generators G1 1000 MVA 15 kVX"-X2 0.18, Xo 0.07 per unit G2 1000 MVA 15 kV X: X, = 0.20, X,-0.10 per unit G3 500 MVA 13.8 kV X: X,-0.15, X,-0.05 per unit G4 750 MVA 13.8 kV X,-0.30, X,-0.40,...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which ...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
The ratings of the components shown in the one-line diagram are G1: 25 MVA, 13.8 kV, x-0.15 pu G2:15MVA, 13 kV, x = 0.1 5 pu. TI : 25 MVA, 13.2/69 kV, x-0. I 1 pu T2: 25 MVA, 69/13.2 kV,x-0.220 pu Tr...
The ratings of the components shown in the one-line diagram are G1: 25 MVA, 13.8 kV, x-0.15 pu G2:15MVA, 13 kV, x = 0.1 5 pu. TI : 25 MVA, 13.2/69 kV, x-0. I 1 pu T2: 25 MVA, 69/13.2 kV,x-0.220 pu Transmission line: j65 ohms/pha bus 2 BE 165Ω ISMVA e ratings of generator 1 as base valu 25MVA 13.8 kV 1 5% 69113.2 kV13kV 1 1% 13.2169k 1 1% 1- Draw the reactance diagram. 2- Find the Y-bus...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which ...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
The component parameters for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 120° pu and Zx-j0.1 pu. Table 1 Ratings X2-Xi (pu)Xo (pu) 0.05 0.10 0.20 0.20 Components G1, G2 200 MVA, 20 kV 0.10 0.10 0.10 0.10 T1, T2, T3200 MVA, 20/200 kV L1 200 MVA, 200 kV し2 200 MVA, 20 kV (a) Draw the three sequence networks and determine the per-unit Thevenin impedance of each sequence network seen from...
can you calculating this question and explain why?
thanks
The ratings and sequence reactances of the components for the power system shown in Figure 2 are given in Table 1. The pre-fault voltage is 1/0° per unit (pu). Bus 8 L3 Bus 1 T1 Bus 4 T2 Bus 2 Bus 5 L1 L2 G1 Bus 3 T3 Bus 7 Bus 6 D.6975 Figure Draw the per unit impedance sequence networks and determine the per unit (a) Thevenin impedances of the...
The reactance data for the power system shown in figure 10.30 in
per unit on a common base is as follows:
*************Remember calculations are needed at bus 2
****************
10.15. The reactance data for the power system shown in Figure 10.30 in per unit on a common base is as follows Item X1 G1 0.10 0.10 0.05 G2 0.10 0.10 0.05 T, 0.25 0.25 0.25 T 0.25 0.25 0.25 Line 1-2 0.30 0.30 0.50 Ti 1 3 2 FIGURE 10.30...
The zero-, positive-, and negative-sequence bus impedance matrices for a three bus power system are given below 5. T0.10 0.15 0.121 Bu0.15 0.10 0.08 pu [0.16 0.10 0.15] Lo.15 0.14 0.30 0.12 0.08 0.35 ZBus ZBus0.10 0.20 0.14 pu Determine the per unit fault current and the bus voltages during fault for (a) A bolted three-phase fault at bus 2. (b) A bolted single line-to-ground fault at bus 2. (c) A bolted line-to-line fault at bus 2 (d) A bolted...
Please help me to answer those question and answer with PHASOR
MAGNITUDE and PHASE ANGLE
Part 1:
Taking the rated power of generator G1 as the base power, and
the transformer T1 low-voltage
side rated voltage as the base voltage, calculate the Thevanin’s
equivalent zero-sequence
impedance, positive sequence impedance and the negative sequence
impedance viewed from
Bus-2. Specify your answers in per-unit.
Part 2:
Assuming the pre-fault bus voltages are at 1.02 pu, calculate the
fault currents in each phase...
Assuming there is a FAULT at BUS 3, Determine the thevenin
equivalent of each series network as viewed from the fault bus.
Given:
-Prefault voltage is 1.0 per unit
-Prefault load currents and delta-wye transformer phase shifts
are neglected
Synchronous generators G1 1000 MVA 15 kVX"-X2 0.18, Xo 0.07 per unit G2 1000 MVA 15 kV X: X, = 0.20, X,-0.10 per unit G3 500 MVA 13.8 kV X: X,-0.15, X,-0.05 per unit G4 750 MVA 13.8 kV X,-0.30, X,-0.40,...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
The ratings of the components shown in the one-line diagram are G1: 25 MVA, 13.8 kV, x-0.15 pu G2:15MVA, 13 kV, x = 0.1 5 pu. TI : 25 MVA, 13.2/69 kV, x-0. I 1 pu T2: 25 MVA, 69/13.2 kV,x-0.220 pu Transmission line: j65 ohms/pha bus 2 BE 165Ω ISMVA e ratings of generator 1 as base valu 25MVA 13.8 kV 1 5% 69113.2 kV13kV 1 1% 13.2169k 1 1% 1- Draw the reactance diagram. 2- Find the Y-bus...
Bus A Bus B R1 TI ine 1 20% 80% line 2 T2 R2 110 kV 11 kV The fault is located at point F, which is 20% of the total line 2 length from Bus B Fault MVA 1524.20471 Three-phase fault level in MVA at bus A SPFL (kA) 8 MVA1 MVA2 X1 (96 X2 (96) R1 (2) R2 (Q) z' (Q) Zo (2) Rf (Q) Single phase to ground fault level (kA) at bus A Transformer 1 MVA...
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