Question

Ethylene is produced by the dehydrogenation of ethane and the following reactions took place C2H6 → C2H4 + H2 C2H6 + H2 → 2CH) C2H4 + C2H6 → C3H6 + CH4 Using extent of reaction. Calculate the % conversion of C2H6 and % Yield of C2H4, if the product gas analysis shows 8.82 % C2H6, 38.23% C2H4, 2.94% C3H6, 14.71% CH4 and 35.30 % H2.

Answer 1

sol Cat6 & Caty + Hå {r Shot H₂ ach QH4 + Gho Shot chy نیا Basis: 100 moles product gas 8.82 moles Ca Hot 38.23 noles C₂H4 +2.94 notes Cat6+ 14.71 noles CH4 + 35:3 and thy yout -n" + vĘ, ŁVEVI V {3 in noux + C3H6 H % Ez 2.94 43 out inº n + 2x + 3 City moty 14,71 = aag + 2.94 aid 14.71 -2.94 5.885 moles les nia +&, - Er 35.3 - &, - 5.885 &, = 41.185 moks

out in 'Ca rate - En, - Ex-&g 8.82 - bir Cho - 41185- 5.885 -22.94 in 50.01 +8.8v - 58.83 moly "Cat6 Note: [feed contains only Sto moles of Qto converted x 100 % conversion of Cats modes of She fed 58.83 - 8.82 X100 58-83 0.85 x 100 - 85% moly of Ghy in product X100 % yield of CH4 mols of GH4 would've formed if all the Cg46 converted to she 38.23 x 100 58.8381 4 stiochiamere Coefkent 64.98%