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1S om in front of a converging (convex) lens with a o) A 7 om sal ofject is placed 1 a) 15 points) Where the image is located
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Answer #1

1/f=1/v -1/u, v=30/7=4.28cm, real and inverted image

v/u=30/7)/15=0.285= -hi/ho ,. Hi=-2cm

So the image is real inverted and 2cm of image height

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