Given the following information in a, b, and c (i.e. the p value), would your decision...
Given the following information, would your decision be to reject or fail to reject the null hypothesis? In addition, briefly explain what your decision means for the research problem. Keep in mind that the level of significance is .05. The null hypothesis that there is no relationship between the amount of coffee consumed and a student’s GPA (p = .05).
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H :p> 0.554, the test statistic is z = 1.34. O A. 0.0901; fail to reject the null hypothesis O B. 0.9099; fail to reject the null hypothesis OC. 0.0901; reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p>0.554, the test statistic is z = 1.34. O A. 0.0901; reject the null hypothesis OB. 0.9099; fail to reject the null hypothesis OC. 0.0901; fail to reject the null hypothesis OD. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Hy:p0.377, the test statistic is z = 3.06. O A. 0.0022; fail to reject the null hypothesis OB. 0.0011; reject the null hypothesis OC. 0.0022; reject the null hypothesis OD. 0.0011; fail to reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).The test statistic in a right-tailed test is z=0.52. A. 0.6030; fail to reject the null hypothesis B. 0.3015; reject the null hypothesis C. 0.0195; reject the null hypothesis D. 0.3015; fail to reject the null hypothesis
Question 21 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H1: p. 0.612, the test statistic is z = -3.06. 1) 0.0022; fail to reject the null hypothesis 2) 0.0011; fail to reject the null hypothesis 3) 0.0011; reject the null hypothesis 4) 0.0022; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).With Upper H 1H1: pgreater than>0.554, the test statistic is zequals=1.34. A. 0.0901; reject the null hypothesis B. 0.0901; fail to reject the null hypothesis C. 0.9099; fail to reject the null hypothesis D. 0.1802; reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Upper H 1 : pgreater than 0.554, the test statistic is zequals 1.34. A. 0.0901; reject the null hypothesis B. 0.0901; fail to reject the null hypothesis C. 0.9099; fail to reject the null hypothesis D. 0.1802; reject the null hypothesis
Question 18 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z = -1.63. 1) 0.9484; fail to reject the null hypothesis 2) 0.1032; fail to reject the null hypothesis 3) 0.0516; fail to reject the null hypothesis 4) 0.0516; reject the null hypothesis
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis. With H PE 0.714, the test statistic is z = 2.21. O 0.0136; reject the null hypothesis 0.0136; fail to reject the null hypothesis 0 0.0272; reject the null hypothesis O 0.0272; fail to reject the null hypothesis.