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The maximum catalytic rate of an enzyme is defined as the turnover number (also called kcat)and...

The maximum catalytic rate of an enzyme is defined as the turnover number (also called kcat)and is the maximum number of reactions a single active site can carry out per second for a given concentration of enzyme.

i.Would a competitive inhibitor reduce the turnover number for an enzyme?Why?

ii.Would an irreversible inhibitor reduce the turnover number for an enzyme?Why?

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Answer #1

Turnover number Kcat = Vmax / ETotal

Competitive inhibitor does not reduce the turnover number for an enzyme because Vmax is not change in competitive inhibitor and it becomes constant with presence or absence of inhibitor. So, Turnover number also become same in both the condition.

In irreversible inhibitor reduce the turnover number for an enzyme because Vmax is decrease. So turnover number also low compare to absence of inhibitor.

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