Question

1. Answer the following questions related to Lecture 19 on registers and counters: . Consider the serial adder on slide 10. Let registers A and B be bit shift registers, and assume that the Shift Control input is set to the "shift right" mode. Suppose that the initial contents of registers A, B, and the D flip flop are A-0110, B-0011, and Q-0. What are the contents of A, B and the D lip flop.. - after one clock edge. - after two clock edges. - after three clock edges. - after four clock edges. Is this final state of A what you expect? Explain. . Consider the universal shift register of slide 12、Let the initial contents of the four flip flops be (from left to right) 0,1,0,1, and assume unchanging values of Isllo 1110, Serial input for shift right" 0, and "Serial input for shift left"-1. What are the contents of the four flip flops after... - after one clock edge, assuming that on this first edge SSo 01 - after two clock edges, assuming that on this second edge SSo 11. after three clock edges, assuming that on this third edge s,s, . Answer the question posed on Slide 14: Why negative edge triggered flip . Answer the question posed on Slide 17: Why does the polarity of the clock 10. - after four clock edges, assuming that on this fourth edge S1So 00 flops for the up counter and positive for the down counter? edge not matter in the synchronous counter? . Redesign the counter of Slide 17 using D flip flops

Answer 1

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