Here, 1/v = 1/6 - 1/18
=> v = 9 cm
=> distance of image from lens = 9 cm (right side of the lens)
=> image formed is real .
For two convex lenses .
=> first image distance = 9 cm
=> 1/v = 1/6 - 1/3
=> v = - 6 cm
=> final image distance = - 6 cm (right side from lens 2)
a convex (converging) lens of focal length 6 centimeters as shown in the picture: 6 cm...
An object is placed 15.0 cm to the left of a convex (converging) lens of focal length 20.0 cm. The image of this object is located (Figure out if the image is real or virtual, it will help to locate the image] O 60.0 cm to the left of the lens. O 60.0 cm to the right of the lens. O 8.57 cm to the right of the lens. O 8.57 cm to the left of the lens. Question 8...
A converging lens with a focal length of 4.9 cm is located 20.9 cm to the left of a diverging lens having a focal length of -11.0 cm. If an object is located 9.9 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. a) Where is the image located as measured from the diverging lens? b) What is the magnification? c) Also determine, with respect to the original object...
A converging lens has a focal length of 7.5 cm. An object is placed 5 cm from the lens. a. Draw the rays tracing diagram to locate the image. Is the image real or virtual? b. Calculate the location and the magnification for this image.
A converging lens has a focal length of 6.0 cm A.) Locate the position of the images for the object distance of 4.0cm B.) Find the height of the image of an object 1.0 cm high C.) State whether the image is real, virtual, upright, or inverted D.) Draw a detailed and proportional ray diagram for this situation
A converging lens with a focal length of 4.2 cm is located 20.7 cm to the left of a diverging lens having a focal length of -11.5 cm. If an object is located 9.2 cm to the left of the converging lens, locate and describe completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? Submit Answer Tries 0/10 What is the magnification? Submit Answer Tries 0/10 Also determine, with...
A converging lens with a focal length of 6.0 cm is located 24.0 cm to the left of a diverging lens having a focal length of -13.0 cm. If an object is located 11.0 cm to the left of the converging lens, locate and describ completely the final image formed by the diverging lens. Where is the image located as measured from the diverging lens? 63.81 cm Submit Answer Incorrect. Tries 3/10 Previous Tries What is the magnification? Submit Answer...
A converging lens with a focal length f1 = 9.00 cm is located 18.0 cm to the left of a converging lens with index of refraction of 1.52 and a radius R = 6.24 cm. An object stands 14.0 cm to the left of the first lens in the combination. Draw the Ray diagrams! (a) Locate the final image relative to the lens on the right. (b) Obtain the overall magnification. (c) Is the final image real or virtual? With...
2. A thin converging lens has a focal length of 10.0 cm. An object is placed 30.0 cm from this lens. Use a sheet of the graph paper provided at the back of this manual to draw a ray diagram that shows the image formed by this lens. Use any two of the three principal (or special) rays and an appropriate scale. Hint: you could let 1 cm on your ray diagram represent 5 cm of the actual measurements:this scale...
A converging lens has a focal length of 6.0 cm. a) Locate the position of the images for object distance of 4.0 cm. b) Find the height of the image of an object 1.0 cm high. c) State whether the image is real or virtual and upright or inverted. d) Draw on the paper that you will upload a detailed and proportional ray diagram for this situation. Do that and than enter "OK" in the blank space below to indicate...
Consider a converging lens whose focal length is 6.95 cm. An object is placed on the axis of the lens at a distance of 13.5 cm from the lens. How far is the object's image from the lens? image distance: cm If it can be determined, is the image real or virtual? cannot be determined real virtual If it can be determined, is the image upright or inverted with respect to the object? cannot be determined inverted upright