Given an i-cache using direct mapping with 32 lines and a block size of 16, what are the tag, index, and offset of the reference word 0x123456? What if the cache is 16 lines?
Given an i-cache using direct mapping with 32 lines and a block size of 16, what...
For a 16K-byte, direct-mapped cache, suppose the block size is 32 bytes, draw a cache diagram. Indicate the block size, number of blocks, and address field decomposition (block offset, index, and tag bit width) assuming a 32-bit memory address.
Consider a system with 24 bit addresses, 128 KB cache with 32 byte lines using direct mapping. Divide the address below labeling each part of the address and specify the size of each field in bits. Tag? Line? Offset?
question 2 and 3
2. Determine how many sets of cache blocks will be there for the following Cache memory size (in bytes) Direct Mapped Blocks Size (in bits) 32 64 218 2-way Set Associative Block Size (in bits) 32 64 A 2A6 [0.5 * 16 = 8] 4-way Set Associative Block Size (in bits) 32 64 SK 64K 256K 3. The physical memory address generated by a CPU is converted into cache memory addressing scheme using the following mapping...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are used to access the cache. TAG INDEX OFFSET 31-15 14-8 7-0 a. What is the cache block size (in words)? [13 points] b. How many blocks does the cache have? [12 points]
Problem 6. Suppose we have a computer with 32 megabytes of main memory, 256 bytes of cache, and a block size of 16 bytes. For each configuration below, determine the memory address format, indicating the number of bits needed for each appropriate field (i.e. tag, block, set, offset). Show any relevant calculations. Direct cache mapping and memory is byte-addressable a) Direct cache mapping and memory is word-addressable with a word size of 16 bits b) c) 2-way set associative cache...
A 256kiB (2^18 bytes) cache has a block size of 32 bytes and is 32-way set-associative. How many bits of a 32-bit address will be in the Tag, Index, and Bock Offset?
Please refer the following memory system : Main memory : 64 MB Cache memory: 64 KB Block size of 1 KB 1. Direct Mapping Offset bits? Number of lines in cache? Line number bits? Tag size? 2. Fully Associative Mapping Offset bits? Tag size? 3. 2-way set-associative mapping Offset bits? Number of lines in cache? Set number bits? Tag size? 4. 4-way set-associative mapping Offset bits? Number of lines in cache? Set number bits? Tag size?
Please answer all parts correctly and show your work
3- for a direct mapped cache design with a 32 bit address, the following bits of address are used to access the cache Tag Index Offset 31-10 9-5 4-0 Starting from power on, the following byte addressed cache reference are recorded. Address 0 16 132 232 160 1024 30 140 3100180 2180 d. How many blocks are replaced e. What is the hit ratio f. List final state of the cache,...
Q2. Consider a four-way set associative cache with a data size of 64 KB. The CPU generates a 32-bit byte addressable memory address. Each memory word contains 4 bytes. The block size is 16 bytes. Show the logical partitioning of the memory address into byte offset, cache index, and tag components.