Sol.
Reaction :
SO2(g) + NO2(g) <---> SO3(g) + NO(g)
Initial 1.25 1.25 1.25 1.25
Change - x - x + x + x
Equilibrium 1.25 - x 1.25 - x 1.25 + x 1.25 + x
So , K = PSO3 × PNO / ( PSO2 × PNO2 )
0.640 = ( 1.25 + x )2 / ( 1.25 - x )2
( 1.25 + x ) / ( 1.25 - x ) = ( 0.640 )1/2 = 0.8
1.25 + x = 0.8 ( 1.25 - x ) = 1 - 0.8x
1.8x = - 0.25
x = - 0.25 / 1.8 = - 0.1389 atm
Therefore , Equilibrium Partial Pressure of SO3(g)
= 1.25 + x atm
= 1.25 + ( - 0.1389 ) atm
= 1.1111 atm
5 At some temperature, the value of the equilibrium constant for the reaction: SO2 (g) +...
At some temperature, the value of the equilibrium constant for the reaction: SO2 (g) + NO2(g) ↔ SO3(g) + NO(g) has the value K = 0.640. If all four gases are placed into a container, each with an initial partial pressure of 1.25 atm, calculate the equilibriuym partial pressure (in atm) of SO3(g)
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