In the cross aaBbcc X AaBbCc, what would be the probability that the offspring has a phenotype identical to either one of the parents?
Answer:
The probability that the offspring has a phenotype identical to either one of the parents = 1/8
Explanation:
aaBbcc X AaBbCc --Parents
aa x Aa = Aa (1/2) & aa (1/2)
Bb x Bb = BB (1/4), Bb (1/2) & bb(1/4)
cc x Cc = Cc (1/2) & cc (1/2)
Probability of aaBbcc = 1/2 * 1/2 * 1/2 = 1/8
Probability of AaBbCc = 1/2 * 1/2 * 1/2 = 1/8
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