Question 5 10 pts Given the following information: A 7 mu B 28 muc For the...

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Answer 1

Answer #1

Answer:

The proportion of abc/abc = 0.064%

Explanation:

Distance between genes (mu) = Recombinantio frequency (%)

Expectec double crossover frequency = (Single crossover frequency (SCO) b/w a&b) x (Single crossover frequency (SCO) b/w b&c)

= 7% x 28% = 0.0196 = 1.96%

Class of gametes	Genotype	Frequency of reciprocal pair	Numbers	Frequency of each class
Parental	aBC	100%- all recombinant progeny	100-(5.04+26.04+1.96) = 66.96	33.48%
	Abc			33.48%
SCO 1	abc	RF in region 1 = SCO1 - DCO	SCO1 = 7% – 1.96% = 5.04%	2.52%
	ABC			2.52%
SCO 2	aBc	RF in region 2 = SCO2 - DCO	SCO2 = 28% – 1.96% = 26.04	13.02%
	AbC			13.02%
DCO	abC	(RF in region 1) * (RF in region 2)	1.96%	0.98%
	ABc			0.98%

Frequency of gamete, abc = 2.52% = 0.0252

The proportion of abc/abc = 0.0252 * 0.0252 = 0.00064 = 0.064%

Answer 2

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