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27.13 pts) True or False: Li(s) + (aq) - Li' (a)+K(s) is a spontaneous reaction, given...
+ + + + + + + + + Metal Oxidation Reaction Lithium Li(s) - Li+...
+ + + + + + + + + Metal Oxidation Reaction Lithium Li(s) - Li+ (aq) Potassium K(s) K+ (aq) Barium Ba(s) Ba2+ (aq) Calcium Ca(s) Ca2+ (aq) Sodium Na(s) Na+ (aq) Magnesium Mg(s) Mg2+ (aq) Aluminum Al(s) A13+(aq) Manganese Mn(s) Mn2+ (aq) Zn(s) Zn2+ (aq) Chromium Cr(s) Cr3+ (aq) Iron Fe(s) Fe2+ (aq) Cobalt Co(s) Co2+ (aq) Nickel Ni(s) Ni2+ (aq) Tin Sn(s) Sn2+ (aq) Lead Pb(s) Hydrogen H2(8) Copper Cu(s) Cu2+ (aq) Silver Ag(s) Ag+ (aq) Mercury...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g)...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the...
A) Use tabulated electrode potentials to calculate ΔG∘ for the reaction. 2K(s)+2H2O(l)→H2(g)+2OH−(aq)+2K+(aq) B) (Refer to the following standard reduction half-cell potentials at 25∘C: VO2+(aq)+Ni2+(aq)2H+(aq)++2e−e−→ →Ni(s)VO2+(aq) +H2O(l)E∘=−0.23V E∘=0.99V) An electrochemical cell is based on these two half-reactions: Oxidation:Reduction:Ni(s)VO2+(aq,0.024M)+2H+(aq,1.4M)+e−→→Ni2+(aq,1.8M)+2e−VO2+(aq,1.8M)+H2O(l) Calculate the cell potential under these nonstandard concentrations. C) Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V ) Half-reaction E∘ (V ) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) − 0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) − 0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) − 0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) − 0.76...
2. Indicate True or False for the following scenarios and explain if the reaction occurs using...
2. Indicate True or False for the following scenarios and explain if the reaction occurs using “higher than" and "lower than" using the sample table 3. True/False Scenario Justification Silver metal will dissolve in nitric acid, liberating H2 gas. Chromium metal can dissolve in dilute HCI. Oxygen in moist air can oxidize Fe2+ to Fe3+ Tin metal will reduce Co2+, but not Sn4+ 178 Page (intel V IA "ost Lab Questions: To receive full credit, you must SHOW ALL YOUR...
List the electrochemical series you developed from this lab based on the experimental values you obtained....
List the electrochemical series you developed from this lab
based on the experimental values you obtained. Compare this to a
published electrochemical series list, like the one in your
eScience lab manual. Is yours different? If so, in what way is it
different?
Metal | Al (Trial 1) 2.5 g Al (Trial 2) Zn (Trial 1) Filter Paper Mass (9) Filter paper + Cu Mass (g) Cu Mass (g) Avg. Cu Mass (g) 2.3 g 2.9 g 0.6 g 0.4...
please help, thanks! 7. What is the correct cell notation for the reaction below? Cd(aq)+Ni(s)-Cd(s)+ Ni(aq)...
please help, thanks!
7. What is the correct cell notation for the reaction below? Cd(aq)+Ni(s)-Cd(s)+ Ni(aq) a. Cd Cd| Ni | Ni d. Ni Cd I N | Ca b. Cd CdNi | Ni e. Cd |Cd Ni Ni 8. Calculate AS for the dissociation of dinitrogen tetraoxi de at 25°C NOdg) 2NO:(g) AG, J/mol)AH, J/mol) Substance NO) NOdg) +33.2 +51.3 +97.9 +9.2 d. +0.076 kJ K a.-2.10 kJ/K e +2.10kJ/K b. -0.550 kJ/K c.-0.208 kJ/K 9. Use the standard...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq,...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
6. Based on the activity series, which single displacement reaction will not occur? Mg(s) + 2HCl(aq)...
6. Based on the activity series, which single displacement reaction will not occur? Mg(s) + 2HCl(aq) - MgCl2 (aq) + H2(g) SnBr2 (aq) + Zn (s) --- ZnBrz (aq) + Sn (s) Mg(s) + ZnCl2 (aq) --- MgCl, (aq) + Zn (s) Zn (s) + 2HNO, (aq) + 2AGNO, (aq) + H2 (8) SnBrz (aq) + Cu(s) -- CuBr2 (aq) + Sn (s) Question 7 1 pts 7. Based on the definition of oxidation and reduction, which of the following...
need help with the rest of the table EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE...
need help with the rest of the table
EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...
please solve both questions to get thumps up. Experiment Electrochemistry Question 7 3 pts to determine...
please solve both questions to get thumps up.
Experiment Electrochemistry
Question 7 3 pts to determine the For the preceding cell, use the table linked here standard cell potential. 0.92 0.85 Sn2 STANDARD REDUCTION POTENTIALS IN AQUEOUS SOLUTION AT 25°C Half-reaction E"(V) Fe) +2 2F" 2.87 Co + Co2 1.82 Au! +36 Au(s) CI,($)+2 2 CI 0,()+ 4H+ + 4e 2 H,O(1) 1.23 Bry(I)+ 2e 2 Br 2 Hg2+ + 2 Hg2+ Hg2+ + 2 Hg(1) Age + Ag(s) 0.80...
+ + + + + + + + + Metal Oxidation Reaction Lithium Li(s) - Li+ (aq) Potassium K(s) K+ (aq) Barium Ba(s) Ba2+ (aq) Calcium Ca(s) Ca2+ (aq) Sodium Na(s) Na+ (aq) Magnesium Mg(s) Mg2+ (aq) Aluminum Al(s) A13+(aq) Manganese Mn(s) Mn2+ (aq) Zn(s) Zn2+ (aq) Chromium Cr(s) Cr3+ (aq) Iron Fe(s) Fe2+ (aq) Cobalt Co(s) Co2+ (aq) Nickel Ni(s) Ni2+ (aq) Tin Sn(s) Sn2+ (aq) Lead Pb(s) Hydrogen H2(8) Copper Cu(s) Cu2+ (aq) Silver Ag(s) Ag+ (aq) Mercury...
2. Indicate True or False for the following scenarios and explain if the reaction occurs using “higher than" and "lower than" using the sample table 3. True/False Scenario Justification Silver metal will dissolve in nitric acid, liberating H2 gas. Chromium metal can dissolve in dilute HCI. Oxygen in moist air can oxidize Fe2+ to Fe3+ Tin metal will reduce Co2+, but not Sn4+ 178 Page (intel V IA "ost Lab Questions: To receive full credit, you must SHOW ALL YOUR...
List the electrochemical series you developed from this lab
based on the experimental values you obtained. Compare this to a
published electrochemical series list, like the one in your
eScience lab manual. Is yours different? If so, in what way is it
different?
Metal | Al (Trial 1) 2.5 g Al (Trial 2) Zn (Trial 1) Filter Paper Mass (9) Filter paper + Cu Mass (g) Cu Mass (g) Avg. Cu Mass (g) 2.3 g 2.9 g 0.6 g 0.4...
please help, thanks!
7. What is the correct cell notation for the reaction below? Cd(aq)+Ni(s)-Cd(s)+ Ni(aq) a. Cd Cd| Ni | Ni d. Ni Cd I N | Ca b. Cd CdNi | Ni e. Cd |Cd Ni Ni 8. Calculate AS for the dissociation of dinitrogen tetraoxi de at 25°C NOdg) 2NO:(g) AG, J/mol)AH, J/mol) Substance NO) NOdg) +33.2 +51.3 +97.9 +9.2 d. +0.076 kJ K a.-2.10 kJ/K e +2.10kJ/K b. -0.550 kJ/K c.-0.208 kJ/K 9. Use the standard...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
6. Based on the activity series, which single displacement reaction will not occur? Mg(s) + 2HCl(aq) - MgCl2 (aq) + H2(g) SnBr2 (aq) + Zn (s) --- ZnBrz (aq) + Sn (s) Mg(s) + ZnCl2 (aq) --- MgCl, (aq) + Zn (s) Zn (s) + 2HNO, (aq) + 2AGNO, (aq) + H2 (8) SnBrz (aq) + Cu(s) -- CuBr2 (aq) + Sn (s) Question 7 1 pts 7. Based on the definition of oxidation and reduction, which of the following...
need help with the rest of the table
EXPERIMENT 10 DETERMINATION OF THE ELECTROCHEMICAL SERIES PURPOSE To determine the standard cell potential values of several electrochemical coll INTRODUCTION The basis for an electrochemical cell is an oxidation reduction Corredor be divided into two half reactions reaction. This reaction can Oxidation half reaction Gloss of electrons) takes place at the anode, which is the positive electrode that the anions migrate to Chence the name anode) Reduction half reaction (gain of electrons)...
please solve both questions to get thumps up.
Experiment Electrochemistry
Question 7 3 pts to determine the For the preceding cell, use the table linked here standard cell potential. 0.92 0.85 Sn2 STANDARD REDUCTION POTENTIALS IN AQUEOUS SOLUTION AT 25°C Half-reaction E"(V) Fe) +2 2F" 2.87 Co + Co2 1.82 Au! +36 Au(s) CI,($)+2 2 CI 0,()+ 4H+ + 4e 2 H,O(1) 1.23 Bry(I)+ 2e 2 Br 2 Hg2+ + 2 Hg2+ Hg2+ + 2 Hg(1) Age + Ag(s) 0.80...
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