Question

In a device to produce drinking water, humid air at 32°C, 90% relative humidity and 1 atm is cooled to 5°C at constant pressure.. If the duty on the unit is 2,200 kW of heat is removed from the humid air, how much water is produced and what is the volumetric flow rate of air entering the unit? Data: Air at 32°C has H- o.204 kJ/mol and at 5°C has H 576 kJ/mol H of steam can be found on the steam tables - vapor at 32°C and 1 atm; vapor at 5°C and liquid at 5°C. Assume the volume of the humid air follows the ideal gas law. To solve the problem, determine the mole fractions of water and dry air at the inlet and outlet. Write the number of moles in each box under the n dot columns in terms of a single variable. Then solve according to outout inin Reference states: air at 25°C, 1 atm; H2O at triple point species n_dot mol/min H_hat (kJ/mol) n_dot mol/min H_hat (kJ/mol) air H20 (v H20 (1 0.576 45.19 0.378 0.204 46.08

Answer 1