Homework Answers
This is a case of sex linked inheritance.11small numbers are of those females which are having both alleles for the concerned character ie for miniature wings and sebal body.carriers as well as males will not show these features as these are recessive and linked to x chromosomes
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In Drosophilia, S = normal, s = sable body: W = normal, w = miniature wing....
In Drosophilia, S normal. s-sable hody: W-normal., w miniature wing. In a cross between a heterozygous...
In Drosophilia, S normal. s-sable hody: W-normal., w miniature wing. In a cross between a heterozygous normal fly (heterory gous for both traits) and a sable -bodied, miniature-winged fly, the results were 90 normal lies, 90 with a sable body and miniature wings. 11 with a normal body and miniature wings, and 11 with a sable body and normal wings. Show your work (5) What inheritance pattern explains these results? Why is the explanation for the small number of 11...
could someone help me figure out how to do these pleaseeee A female fruit fly who...
could someone help me figure out how to do these
pleaseeee
A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...
I included everything here , but i only need help with parts C-F You are working...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed...
Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed male. The Fl generation all have normal wings and red eyes. The FI offspring are crossed with miniature-winged, vermillion-eyes flies. The following offspring of that cross were counted. 233 normal wing, red eye 247 miniature wing, vermilion eye 7 normal wing, vermilion eye 13 miniature, red eye a) Explain what a testcross is (1 point). b) What is the expected phenotypic ratio from a...
11) The ailele for wrinkled wings (W) is dominant to the normal wing allele (w) in...
11) The ailele for wrinkled wings (W) is dominant to the normal wing allele (w) in fruit flies. If a fruit fly population is at Hardy-Weinberg equilibrium and 91% of flies have wrinkled wings, what are the three genotype frequencies? (6 points)
In Drosophila, b+ is the allele for normal body color and at the same gene b...
In Drosophila, b+ is the allele for normal body color and at the same gene b is the allele for black body color. A second gene controls wing shape. The shape can be either normal (vg+) or vestigial (vg). A cross is made between a homozygous wild type fly and fly with black body and vestigial wings. The offspring were then mated to black body, vestigial winged flies. The following segregation ratio was observed: Phenotype # Observed Wild Type (normal,...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of this test cross: Will only be of two phenotypes if the test cross fly is homozygous for both traits. Will only be of two phenotypes if the gray-bodied/long-winged fly is homozygous for both traits. Will be of four genotypes if the gray-bodies/long-winged fly is heterozygous for both traits. Will be of four genotypes if the test-cross fly is heterozygous for both traits. None of...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed, and a homozygous normal winged female fly was crossed to a male with wild type body, wild type eyes, and cut wings. The Fi females were wild type for all three traits, while the Fi males had yellow bodies, white eyes, normal wings. The Fi females were crossed to yellow bodied, white eyed, cut wing males. The resulting F2 progeny...
Questions 34 to 41 deal with linkage and mapping: see Sanders & Bowman 2015/2018 - Chapter...
Questions 34 to 41 deal with linkage and mapping: see Sanders & Bowman 2015/2018 - Chapter 5. 34. Two true-breeding Drosophila were crossed: a normal-winged, normal-bodied female and a curved-winged, speck-bodied male. The F, all have normal wings and normal bodies. Female F1 offspring were then crossed with curved-winged, speck- bodied male flies. The following offspring of that cross were counted: 174 normal wings, normal body (Neither the allele for curved wings nor 169 curved wings, speck body that for...
Drosophila genetics hw. Can someone help explain this You are doing a genetics experiment with the...
Drosophila genetics hw. Can someone help explain this
You are doing a genetics experiment with the fruit fly. In the "P" generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings. All of the flies in the F1 generation are brown and have normal wings. Indicate the alleles associated with dominant phenotypes by uppercase letters and alleles associated with recessive phenotypes by lowercase letters. Assume the genes are...
In Drosophilia, S normal. s-sable hody: W-normal., w miniature wing. In a cross between a heterozygous normal fly (heterory gous for both traits) and a sable -bodied, miniature-winged fly, the results were 90 normal lies, 90 with a sable body and miniature wings. 11 with a normal body and miniature wings, and 11 with a sable body and normal wings. Show your work (5) What inheritance pattern explains these results? Why is the explanation for the small number of 11...
could someone help me figure out how to do these
pleaseeee
A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...
I included everything here , but i only need help with parts
C-F
You are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that you have no information. You first look at 2 genes, each with two alleles: "Borb" for body color and "Wor w" for wing surface. The red body phenotype is dominant to the yellow body...
Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed male. The Fl generation all have normal wings and red eyes. The FI offspring are crossed with miniature-winged, vermillion-eyes flies. The following offspring of that cross were counted. 233 normal wing, red eye 247 miniature wing, vermilion eye 7 normal wing, vermilion eye 13 miniature, red eye a) Explain what a testcross is (1 point). b) What is the expected phenotypic ratio from a...
11) The ailele for wrinkled wings (W) is dominant to the normal wing allele (w) in fruit flies. If a fruit fly population is at Hardy-Weinberg equilibrium and 91% of flies have wrinkled wings, what are the three genotype frequencies? (6 points)
In Drosophila, b+ is the allele for normal body color and at the same gene b is the allele for black body color. A second gene controls wing shape. The shape can be either normal (vg+) or vestigial (vg). A cross is made between a homozygous wild type fly and fly with black body and vestigial wings. The offspring were then mated to black body, vestigial winged flies. The following segregation ratio was observed: Phenotype # Observed Wild Type (normal,...
A gray-body fly with long wings is subjected to a test cross. The F1 progeny of this test cross: Will only be of two phenotypes if the test cross fly is homozygous for both traits. Will only be of two phenotypes if the gray-bodied/long-winged fly is homozygous for both traits. Will be of four genotypes if the gray-bodies/long-winged fly is heterozygous for both traits. Will be of four genotypes if the test-cross fly is heterozygous for both traits. None of...
4. There are three genes on the X-chromosome in drosophila, yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed, and a homozygous normal winged female fly was crossed to a male with wild type body, wild type eyes, and cut wings. The Fi females were wild type for all three traits, while the Fi males had yellow bodies, white eyes, normal wings. The Fi females were crossed to yellow bodied, white eyed, cut wing males. The resulting F2 progeny...
Questions 34 to 41 deal with linkage and mapping: see Sanders & Bowman 2015/2018 - Chapter 5. 34. Two true-breeding Drosophila were crossed: a normal-winged, normal-bodied female and a curved-winged, speck-bodied male. The F, all have normal wings and normal bodies. Female F1 offspring were then crossed with curved-winged, speck- bodied male flies. The following offspring of that cross were counted: 174 normal wings, normal body (Neither the allele for curved wings nor 169 curved wings, speck body that for...
Drosophila genetics hw. Can someone help explain this
You are doing a genetics experiment with the fruit fly. In the "P" generation, you cross two true-breeding flies. The female parent is brown and wingless and the male parent is black with normal wings. All of the flies in the F1 generation are brown and have normal wings. Indicate the alleles associated with dominant phenotypes by uppercase letters and alleles associated with recessive phenotypes by lowercase letters. Assume the genes are...
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