An object 3 cm high is placed 40 cm in front of a concave spherical mirror with radius of curvature of 60 centimeters and an image of the object is observed.
part a Make a drawing of the system
part b Explain how you would calculate the focal length and the position of the image.
part c Calculate the height of the image.
part d Indicate if the image is real or virtual and if it is upright or inverted.
given
object height, h = 3 cm
object distance, u = 40 cm
radius of curvature, R = 60 cm
a)
b) focal length, f = R/2 = 60/2 = 30 cm
let v is the image distance.
use, 1/u + 1/v = 1/f
1/v = 1/f - 1/u
1/v = 1/30 - 1/40
v = 120 cm <<<<<<<----------------Answer
part c) magnification, m = -v/u
= -120/40
= -3
image height, h' = m*object hight
= -3*3
= -9 cm <<<<<<<----------------Answer
part d) The image is real and inverted.
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