Management has been having a quality problem with one of its computer lines. Three samples of 40 computers each have been taken and recorded below. You have been asked to examine the following samples and their defects to determine the average percentage defective. Using a 95 percent confidence level, graph the control chart. Make some conclusions about the process.
SAMPLE
1 2 3
Number of Errors 5 5 9
Answer: 95% confidence corresponds to z value of 1.96
Day | Defectives | Observations |
1 | 5 | 40 |
2 | 5 | 40 |
3 | 9 | 40 |
total | 19 | 120 |
steps and formulas, for z=1.96 | ||
Proportion of defects=Pbar | total defectives/total observations | 0.158 |
Q= | 1-P | 0.842 |
N= | average sample size | 40 |
Standard deviation | squareroot(P*Q/N) | 0.058 |
UCL= | P + z*squareroot(P*Q/N) | 0.271 |
LCL= | P - z*squareroot(P*Q/N) | 0.045 |
P chart
The process is in control: As we can see that NO sample is beyond control limits in charts
use the table below
Day | Defectives | Observations | proportion of defect=defectives/observations | P | UCL | LCL |
1 | 5 | 40 | 0.125 | 0.158 | 0.271 | 0.045 |
2 | 5 | 40 | 0.125 | 0.158 | 0.271 | 0.045 |
3 | 9 | 40 | 0.225 | 0.158 | 0.271 | 0.045 |
Management has been having a quality problem with one of its computer lines. Three samples of...
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