a. We know that Km = S at v = 1/2(Vmax)
Given that Vmax = 1; from the plot, it can be seen that at v = 0.5, S = 1
Hence, Km = 1
b. Competitive inhibitors increase Km without altering Vmax. The only graph that is showing this is B.
c. At v = 0.5, S = 2. Hence, Km = 2.
d. Competitive inhibition increases Km without altering Vmax. In competitive inhibition, the inhibitor competes for the active sites of an enzyme and decreases the extent of binding of the substrate to the enzyme, resulting in higher Km and unaltered Vmax.
Use the Michaelis-Menten Plot to answer question 11. If V max for the black curve is...
The equation that describes the above Michaelis-Menten curve: Vo TS]+K Vmax [S] Michaelis-Menten Equation Lineweaver and Burke manipulated the Michaelis-Menten equation to yield: Ko V I S Vmax [S] Lineweaver-Burke Equation Linewenver Burke Equation If you plot 1/ V. vs. 1/[S], you get the following Lineweaver-Burke plot: 1/V. Slope = km/Vmax Intercept = -1/KM -Intercept = 1/Vmax 1/[S] Which is easier to calculate values for Km and Vmax, using the linear (y=mx+b) Lineweaver-Burke Plot or the Michaelis-Menten curve?
Write the equations that describe the Michaelis-Menten and the Lineweaver-Burk double-reciprocal plots. Draw examples of each plot, demonstrating how Km and Vmax can be determined. On the same graphs, draw another plot where the same enzyme-catalyzed reaction is subjected to inhibition by a competitive inhibitor.
(I need help with part C, Drawing the expected Michaelis-Menten plot; Do NOT draw the Lineweaver-Burk plot. thanks!) 1. Michaelis-Menten kinetics- use the M-M equation to answer the following: a. An enzyme (5 µM) has a Vmax of 450 mM/min. What is kcat? b. When the substrate concentration is 50 mM, the initial velocity (V0) was measured to be 375 mM/min. Under the conditions described above, calculate the KM. c. Draw the expected Michaelis-Menten plot (label your axes and include...
The kinetics of enzyme catalyzed reactions can be described the Michaelis-Menten equation and the Eadie-Hofstee equation as shown below: V0 = (-Km) V0 / [S] + Vmax a). Please derive the Eadie-Hofstee equation starting from the Michaelis-Menten equation. b). The Vmax and Km of the enzyme catalyzed reaction can be derived from a plot of V0 versus V0/[S]. Please draw one of these plots and explain how do you use it to derive Vmax and Km. c). Please draw a...
Michaelis-Menten plot and Lineweaver-Burk plot calculations: Use provided data to generate both M-M and L-B plots. Use scatter plots with markers on Excel: On the M-M Plot: estimate Vmax, KM On the L-B Plot: determine Vmax, KM, keat, kcat/Km. The total enzyme concentration is 5 uM. Graphs can be 1/2 page. Must be computer generated with all axes labeled. Substrate (mM) V. (mM/s) | 1/[S] (mM1) 1/V. (s/mM) 10 | 0 2.73 5.45 8.17 10.9 40.4 0.124 0.181 0.212 0.228...
The Eadie-Hofstee plot shown below, is an alternative graphical representation of Michaelis-Menten kinetics. t plots the rate (v) versus the ratio of the rate over the substrate concentration (vIS]). This plot is typically used to determine the maximum rate, Vmax, and the Michaelis constant, Km, which can be gleaned from the intercepts and slope. Identify each intercept and the slope in terms of the constants Vmax and Km Eadie-Hofstee Plot y-intercept Slope x-intercept AS
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using the M-M equation that when [S] <<<Km, vo =[S][Et]kcat/Km. 2. What is Vmax? Provide both a mathematical and written description of Vmax? How can Vmax be experimentally altered? How can we use Vmax to determine the turnover number (kcat) of an enzyme-catalyzed reaction? What is the major challenge of determining Vmax from an Michaelis-Menten plot?
1. MICHAELIS-MENTON-(REQUIRED) a. Draw a simple graph, showing the classic Michaelis-Menton plot of enzyme activity as a function of substrate concentration; label both axes. Write the associated Michaelis-Menton equation and show the location of Km and Vmax on your graph. b. Draw a second graph showing the classic Lineweaver-Burk plot; label both axes. Show the location of Km and Vmax on your graph. Discuss which plot is the most useful to determine Vmax. Draw a second line on each graph...