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v/Vmax 0.9 0.8 0.7 0.5 0.4 0.3 0.2 0.1 [SYK Use the Michaelis-Menten Plot to answer question 11. (2pts) a) If Vmax for the black curve is 1, what is Km? b) hich graph (A, B, C, or D) represent a competitive inhibition? c) Determine Kum for your answer in b d) How does competitive inhibition affect Vmax and Km? 10

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Answer #1

a. We know that Km = S at v = 1/2(Vmax)

​Given that Vmax = 1; from the plot, it can be seen that at v = 0.5, S = 1

Hence, Km = 1

b. Competitive inhibitors increase Km without altering Vmax. The only graph that is showing this is B.

c. At v = 0.5, S = 2. Hence, Km = 2.

d. Competitive inhibition increases Km without altering Vmax. In competitive inhibition, the inhibitor competes for the active sites of an enzyme and decreases the extent of binding of the substrate to the enzyme, resulting in higher Km and unaltered Vmax.

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