In a pair-matched case-control study of risk factors for carcinoma, dietary history of 30 patients with the disease and 30 control subjects were collected. Below is a table that summarizes their history of corn and corn oil consumption.
Pairs | Cases - Carcinoma patients | Controls - healthy subjects |
1 | Yes | Yes |
2 | Yes | Yes |
3 | Yes | Yes |
4 | Yes | Yes |
5 | Yes | Yes |
6 | Yes | Yes |
7 | Yes | No |
8 | Yes | No |
9 | Yes | No |
10 | Yes | No |
11 | Yes | No |
12 | Yes | No |
13 | Yes | No |
14 | Yes | No |
15 | Yes | No |
16 | Yes | No |
17 | Yes | No |
18 | Yes | No |
19 | Yes | No |
20 | No | No |
21 | No | No |
22 | No | No |
23 | No | No |
24 | No | No |
25 | No | No |
26 | No | Yes |
27 | No | Yes |
28 | No | Yes |
29 | No | Yes |
30 | No | Yes |
a. What is estimated odds ratio? what is the 95% confidence interval of population odds ratio?
b. Perform hypothesis test and see if there is any difference in efficacy between two treatments. level of sig - 0.05. state null and alternate hypothesis, test statistic, p value and your conclusion.
This is the question of case-control data where the counts in this table(table structured using the information above) represent the number of pairs and not the number of individuals.
Cases/control | Yes | No |
Yes | 6 | 13 |
No | 5 | 6 |
No. of Yes-yes pairs are 6, No. of Yes-No pairs are 13, No. of No-Yes pairs are 5, No. of No-No pairs are 6 (from the information provided in the question)
a) Here Yes-Yes and No-No are known as the concordant pairs of the sample and Yes-No and No-Yes are known as discordant pairs. Although there are N = 30 pairs but we are only interested in the discordant pairs which are u = 13 and v = 5.
Odds Ratio =
The confidence interval for odds-ratio =
where z = 1.96 at 95% level of confidence.
Now first let us find
=
= 0.526
Now we will calculate the CI for odds ratio=
=
= -0.076,1.99
Hence the 95% confidence interval for case control data's odd ratio is [-0.076,1.99].
b) Also, When the number of discordant pairs (u + v) is 10 or greater, you can test H0: OR = 1 with McNemar’s chi-square statistic.
Since u+v = 13+5 = 18
H0: OR = 1
H1: OR > 1
The regular and continuity-correct McNemar’s chi squares are shown below:
Because of the relation between the chi-square distributions and z distributions, the above formulas can be re-expressed:
In a pair-matched case-control study of risk factors for carcinoma, dietary history of 30 patients with...
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