Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to
prepare a tube of 1 mL with cells at
2 x 10^5 cells/mL. Pipetting less than 1 μL is hard to do
accurately. Do a dilution if less than 1μL
After dilution,Now that you have your tube of 1 mL with cells at
2 x 10^5/mL, explain how to add 10^4 cells to each
of 10 wells. Do you have enough cells?
The calculations can be made as
follows:
M1V1 = M2V2
Putting values:
6.3*108 * V1 = 1ml * 2*105
Solving for V1: 2*105 / 6.3 *108 or 3.17 *10-4 ml or 0.314 ul.
Since this small volume is difficult to pipette, it is advisable to make two dilution, first half of the original to get a 1:2 state and then adding 0.114 ul of diluent to this dilution and make up to 1ml to get the final desired sample.
Now there is 1 ml dilution containing desired amount of cells. The volume of each well is nearly 200 ul.
In order to divide it into 10 wells, the volume plated in each well must be plated with 1000/200 or 5ul of sample. This 5ul of sample will contain nearly:
(2*105 / 1000) * 5 = 103 cells.
Thus, this dilution does not have enough cells.
Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube of...
1a Your cell suspension is 6.3 x 10^8 cells /mL. Explain how to prepare a tube of 1 mL with cells at 2 x 10^5 cells/mL. 1b Now that you have your tube of 1 mL with cells at 2 x 10^5/mL, explain how to add 10^4 cells to each of 10 wells. Do you have enough cells?
Cells are kept in suspension in RPMI a media for glowing cells. You have 30 mL of a cell suspension at a concentration of 7.2 times 10^6 cells/mL. You need to dilute a portion of these cells such that 100 mu L of the new suspension will deliver 1 times 10^5 cells when plated in the wells of a 96-well microstate plate. How would you dilute some cells so you could prepare 48 such wells? Your answer should account for...
1. You have a bacterial cell culture with a concentration of 1x109 cells/ml. You need to dilute the cells to a concentration of 1x103. What is the correct ratio for this dilution? 2. You add 0.1 ml of a yeast culture to a test tube that contains 9.9 ml of buffer solution. What is the dilution factor of this mixture? 3. In a 1000 µl total dilution volume, the volume of cell culture used is 800 µl. What is the...
you have a 2 ml solution of CHO cells at a concentration of 5.6 x 10^4 cells/mL and need to produce a solution of 56 cells/mL set up detailed serial dilution given 8mL of 4.1 x10^3 cells/ML and need approximitly 100 cells/mL. set up detailed serial dilution by determining the aliquot to be transfered (v1) from the solution to get 100 cells/mL in a final volume of 10 mL given 10mL cell suspension of NIH cells at 3.8 x10^5 cells/ML...
Your stock cell concentration after couting your cells is 2 x 10^6 cell/ml. What volume of cell suspension contains 200,000 cells?
You calculated the live cell concentration to be 1.5 x 10^6 cells/mL. what is the volume of cell suspension needed to seed a T-75 flask with 7.5 x 10^5 cells in 10 mLs of media.
Answer and do the following calculations: 1. Suppose your professor handed you a test tube with 2.0 mL of an E. coli broth culture in it and told you to make a 10–2 dilution of the entire culture. Explain how you would do this. Show your calculations. 2. How would you produce a 10–1 dilution of a 3 mL bacterial sample using the entire 3 mL volume? 3. You have 0.05 mL of an undiluted culture at a concentration of...
How would you prepare 1.5 ml of a 1:1000 dilution of the CB2 primary antibody (1° Ab CB2) in 1% milk solution if 1.5 μl is provided in a tube. Specifically, how much 1% Milk in DPBS will you add to the tube?
1. You prepared a dilution 1 in 2 of trypsinized CHO-K1 cells. Then, you took an aliquot of the cell suspension and counted the cells using a hemocytometer. There were 75 cells in the 16 little squares. Please explain how to get each! a. Calculate the concentration of the cells prior to the dilution. Show your calculations. Use scientific notation to express the result. b. Now, you want to seed a 25cm2 flask with 750,000 cells. Calculate how many ml...
It would be much appreciated if you can help me with the recipe of the buffer above. Thank you. Cells are kept in suspension in RPMI, a media for growing cells. You have 30 mL of a suspension at a concentration of 7.2x10^6 cells/mL. You need to dilute a portion of these cells such that 100 mu L of the new suspension will deliver 1*10^5 cells when plated in the wells of a 96-well microtitre plate. How would you dilute...