Question

A batch culture has a constant specific growth rate of m = 0.2 hr^-1. Due to the presence of a growth inhibitor, the cells also die at a constant (specific) death rate of 0.02 hr^-1 at the same time. What is the doubling time of the culture?

Answer 1

Answer to the above question:

Given, Specific growth rate = 0.2 hour^-1

Specific death rate = 0.02 hour^-1

To calculate, the doubling time we use the following formula:

Doubling time = specific growth rate/ specific death rate

= 0.2/ 0.02

= 10

Therefore doubling time of the culture is 10 times.