Mean generation time = 1 / K
= 1 / 2.4
= 0.4166 day
No= 6 x 105 cells/mL
Nt = 8 x 109 cells/mL
n = Number of generations
So n = ( log Nt - log No) / log 2
= (9.903 - 5.778) / 0.301
= 4.125 / 0.301
= 13.704 generations
Hence t = n / K
= 13.704 / 2.4
= 5.71 days ( ~ 5 days 17 hrs)
An exponentially growing culture has a specific growth rate constant, K = 2.4 day-1. What is...
For practice in the use of these equations, solve the following problems: 1. From the data given, calculate (a) the number of doublings over the total growth period and (b) the generation time during the exponential growth phase. Cells per ml 2.0 x 106 2.5 x 106 8.8 x 106 7.4 x 107 6.3 x 108 1.2 x 109 1.2 x 109 Time in Hours 0 2 4 10 12 2. You need, for experimental purposes at 8 a.m. Monday...
Consider a culture of E. coli growing in exponential phase with a generation time of 20 minutes. Beginning with 2 x 106 cells per ml, how long will it take the culture to reach a density of about 3.2 x 107 cells per ml?
3. You inoculate 1 liter of medium with an E. coli culture to an initial cell density of 104 cells/ml. The culture grows exponentially with a generation time of 20 minutes. What is the culture density after 24 hours?
A batch culture has a constant specific growth rate of m = 0.2 hr-1. Due to the presence of a growth inhibitor, the cells also die at a constant (specific) death rate of 0.02 hr-1 at the same time. What is the doubling time of the culture?
Growth of Bacteria The growth rate of Escherichia coli, a common bacterium found in the human intestine, is proportional to its size. Under ideal laboratory conditions, when this bacterium is grown in a nutrient broth medium, the number of cells in a culture doubles approximately every 20 min. (a) If the initial population is 20, determine the function Q(t) that expresses the growth of the number of cells of this bacterium as a function of time t (in minutes). (b) How long would...
1) If a culture has an instantaneous growth rate constant of 0.00090832 min-1, what is the doubling time of the culture? Express your answer in minutes using exponential notation. 48.2 minutes would be 4.82E1 Round your answer to two decimal places 32.67 minutes would be 3.27E1 2)Given a doubling time of 635 minutes, how long will it take a culture to grow from 14 cells per mL, to 47,621 cells per mL? Report your answer in minutes, rounded to 2...
11.) A culture of bacteria in log phase increases from (Log1o ml) 8.0 to 8.6 in 1.5 h. What is specific growth rate (u) of this culture? What is the generation time (GT)? How many minut does it take for a doubling of cells? After 181 minutes, how many doublings have occurred? 12.) Finish labeling the following plot and determine the μ"ae and Ks of E.coli for glucose at 35°C. Us units of mM for concentration. Linweaver Burk plot E.coli...
Based on the growth data of a bacterial culture presented below, determine μ (specific growth rate). Time (Hour) X (Cell Concentration, Cells/L) 1 1,100,000 2 1,600,000 3 2,620,000 4 3,650,000 5 6,080,000 6 9,900,000 7 18,000,000 8 28,100,000 9 39,100,000 10 70,100,000 11 102,000,000
help me answer quetion 1 please 11 42% & 17:19 4/ Homework 2- ECH160,pdf Quarter 2, 2018-2019 ECH 160Homework 2 Instructor: N.T Linh, Dept. OR&P, HUMG Assigned on 24 May, 2019 Due on 27 May, 2019 Problem 1 A mouse-mouse hybridoma cell line is used to produce monoclonal antibody. Growth in batch culture is monitored with the following results. Time (day) Cell concentration (cells/ml) x 10 0.0 0.45 0.2 0.52 0.65 0.5 0.81 1.5 1.22 1.77 2.13 3.0 3.55 4.02...
e this experiment follows a modified procedure designed to demonstrate only the lag and log phases by using an indirect method foe measuring growth. The indirect method is based on atisie at intervals during the incubation period. Such a procedure does not lend itself to a regular laboratory curve will be plotted usin appears cloudier as the bacteria increase in number by cell division. A tube of bacte- r can measure the n liquid culture, the medium amount of light...