How much solute is required to make 600 ml of a 0.4M solution of Tris buffer....

Question

Question

How much solute is required to make 600 ml of a 0.4M solution of Tris buffer. FW of Tris base = 121.1 grams.

Answer 1

Answer #1

Volume = 600 mL = 600 / 1000 = 0.600 L

Moles = Molarity x volume = 0.4 M x 0.600 L

= 0.24 moles.

Mass of solute = Moles x Molar mass

= 0.24 moles x 121.1 g/mol

= 29.06 g.

Therefore, mass of solute = 29.06 g.

Answer 2

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