Using the data below, determine the real component of the desired pole (which your root locus...
Using the data below, determine the real component of the desired pole (which your root locus would pass through):
Settling Time (Ts) = 5 seconds
Peak Time (Tp) = 1.0 seconds
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Using the data below, determine the real component of the
desired pole (which your root locus...
QUESTION 5 Using the data below, determine the angle (degrees) of the desired pole with respect...
QUESTION 5 Using the data below, determine the angle (degrees) of the desired pole with respect to the origin (counter-clockwise rotation): Hint: Do not include the i" Settling Time (Ts) 5 seconds Peak Time (Tp) 1.0 seconds
Using the data below, determine the angle (degrees) of the desired pole with respect to the...
Using the data below, determine the angle (degrees) of the desired pole with respect to the origin (counter-clockwise rotation) Hint: Do not include the "i" Settling Time (TS) = 0.5 seconds Peak Time (Tp) = 0.1 seconds
A plant with the transfer function Gp(s)-- with unity feedback has the root locus shown in the figure below: (s+2)(s+4) Root Locus 1.5 C(s) 0.5 0.5 1.5 .3 Real Axis (seconds) (a) Determine K of G...
A plant with the transfer function Gp(s)-- with unity feedback has the root locus shown in the figure below: (s+2)(s+4) Root Locus 1.5 C(s) 0.5 0.5 1.5 .3 Real Axis (seconds) (a) Determine K of Gp(s) if it is desired that the uncompensated system has a 10% OS (overshoot) to a step input. (4 points) a 5% overshoot and a peak time Tp 3.1 meets the requirements described in part (b) and achieves zero steady state (b) Compute the desired...
A system having an open loop transfer function of G(S) = K10/(S+2)(3+1) has a root locus...
A system having an open loop transfer function of G(S) = K10/(S+2)(3+1) has a root locus plot as shown below. The location of the roots for a system gain of K= 0.248 is show on the plot. At this location the system has a damping factor of 0.708 and a settling time of 4/1.5 = 2.67 seconds. A lead compensator is to be used to improve the transient response. (Note that nothing is plotted on the graph except for that...
R(s) C(s) G(s)G(s) Given the simple control loop above and the data below, determine the Kp...
R(s) C(s) G(s)G(s) Given the simple control loop above and the data below, determine the Kp gain for the Go(s) PD-controller Peak time (Tp)-0.1 seconds Settling Time (Ts)-0.5 second G(s) = (s+2) / (s^3 + 9m2 + 8s)
3. Root Locus 2 -2 -3 -5 -3 -2 0 Real Axis (seconds Using the plot...
3. Root Locus 2 -2 -3 -5 -3 -2 0 Real Axis (seconds Using the plot above, determine the system's characteristic equation 1+KGH 0
b) Design a PID controller via root-locus to satisfy the following requirements for the controlled system...
b) Design a PID controller via root-locus to satisfy the following requirements for the controlled system 2.9 T,-0.18 The following notation has been used for the system parameters: Percent Overshoot(%)-pos Settling time (s) Peak time (s)- Tp Start by manual calculations for the locations of the poles and zeros of the PID controller to satisfy the requirements. Find the required location of the zero for PD control and introduce PI control. Afterwards, use the Sisotool in MATLAB to simulate the...
Question 5 The root locus of a system is provided in the following figure. C(s) R(s) + (s-2%s -I)...
Question 5 The root locus of a system is provided in the following figure. C(s) R(s) + (s-2%s -I) 2.00 1.50 1.00 . 50 -.50 -2.00 2.00 -2.00 1.00 1.00 Real (a) Find the location of closed-loop system poles (design poles) to provide S -0.707 (use the provided scaled graph to avoid numerical calculations). (b) Find the value of K corresponding to the design poles. (c) Find the value of settling time corresponding to the design poles. (d) It is...
BONUS QUESTION: Would you prefer an alternative controller with a stronger D-component, specifically, H(s)kp(l + 2s),...
BONUS QUESTION: Would you prefer an alternative controller with a stronger D-component, specifically, H(s)kp(l + 2s), if your goal is a fast step response under the same contraints of a single overshoot and peak overshoot of less than 5%? Provide a detailed reason either with time-domain metrics (such as rise time or settling time) or by comparing and discussing the root locus curves for both cases 10 bonus points] Figure 4: Template for the root locus in Problem 2A. Mark...
% We can couple the design of gain on the root locus with a % step-response...
% We can couple the design of gain on the root locus with a
% step-response simulation for the gain selected. We introduce
the command
% rlocus(G,K), which allows us to specify the range of gain, K,
for plotting the root
% locus. This command will help us smooth the usual root locus
plot by equivalently
% specifying more points via the argument, K. Notice that the
first root locus
% plotted without the argument K is not smooth. We...
QUESTION 5 Using the data below, determine the angle (degrees) of the desired pole with respect to the origin (counter-clockwise rotation): Hint: Do not include the i" Settling Time (Ts) 5 seconds Peak Time (Tp) 1.0 seconds
Using the data below, determine the angle (degrees) of the desired pole with respect to the origin (counter-clockwise rotation) Hint: Do not include the "i" Settling Time (TS) = 0.5 seconds Peak Time (Tp) = 0.1 seconds
A plant with the transfer function Gp(s)-- with unity feedback has the root locus shown in the figure below: (s+2)(s+4) Root Locus 1.5 C(s) 0.5 0.5 1.5 .3 Real Axis (seconds) (a) Determine K of Gp(s) if it is desired that the uncompensated system has a 10% OS (overshoot) to a step input. (4 points) a 5% overshoot and a peak time Tp 3.1 meets the requirements described in part (b) and achieves zero steady state (b) Compute the desired...
A system having an open loop transfer function of G(S) = K10/(S+2)(3+1) has a root locus plot as shown below. The location of the roots for a system gain of K= 0.248 is show on the plot. At this location the system has a damping factor of 0.708 and a settling time of 4/1.5 = 2.67 seconds. A lead compensator is to be used to improve the transient response. (Note that nothing is plotted on the graph except for that...
R(s) C(s) G(s)G(s) Given the simple control loop above and the data below, determine the Kp gain for the Go(s) PD-controller Peak time (Tp)-0.1 seconds Settling Time (Ts)-0.5 second G(s) = (s+2) / (s^3 + 9m2 + 8s)
3. Root Locus 2 -2 -3 -5 -3 -2 0 Real Axis (seconds Using the plot above, determine the system's characteristic equation 1+KGH 0
b) Design a PID controller via root-locus to satisfy the following requirements for the controlled system 2.9 T,-0.18 The following notation has been used for the system parameters: Percent Overshoot(%)-pos Settling time (s) Peak time (s)- Tp Start by manual calculations for the locations of the poles and zeros of the PID controller to satisfy the requirements. Find the required location of the zero for PD control and introduce PI control. Afterwards, use the Sisotool in MATLAB to simulate the...
Question 5 The root locus of a system is provided in the following figure. C(s) R(s) + (s-2%s -I) 2.00 1.50 1.00 . 50 -.50 -2.00 2.00 -2.00 1.00 1.00 Real (a) Find the location of closed-loop system poles (design poles) to provide S -0.707 (use the provided scaled graph to avoid numerical calculations). (b) Find the value of K corresponding to the design poles. (c) Find the value of settling time corresponding to the design poles. (d) It is...
BONUS QUESTION: Would you prefer an alternative controller with a stronger D-component, specifically, H(s)kp(l + 2s), if your goal is a fast step response under the same contraints of a single overshoot and peak overshoot of less than 5%? Provide a detailed reason either with time-domain metrics (such as rise time or settling time) or by comparing and discussing the root locus curves for both cases 10 bonus points] Figure 4: Template for the root locus in Problem 2A. Mark...
% We can couple the design of gain on the root locus with a
% step-response simulation for the gain selected. We introduce
the command
% rlocus(G,K), which allows us to specify the range of gain, K,
for plotting the root
% locus. This command will help us smooth the usual root locus
plot by equivalently
% specifying more points via the argument, K. Notice that the
first root locus
% plotted without the argument K is not smooth. We...
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