Solve the difference equation: y(n+1) – 0.2 y(n) – 4 =0 with y(0)=1. Deduce y(5). (do not use z-transform)
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Solve the difference equation: y(n+1) – 0.2 y(n) – 4 =0 with y(0)=1. Deduce y(5). (do...
Consider the difference equation y(n) = -0.6y(n-1) - x(n-1) for n>=0 and y(-1) = 0 1. WITHOUT using Laplace or Z-Transform, determine the unit-impulse response h(n) starting from h(0).
Solve the difference equationy(n + 2) + 4y(n + 1) +3y(n) = 3n with y(0) =0, y(1) = 1
4. (20 points) Use z-transform to solve the difference equation y(k) -1.5y(k-1) + 0.56y(k-2) = x(k) for k> 0 with initial conditions y(-1) = 3, y(-2)=-4, and x(k)= kļu(k).
Question 3. Consider the DT system described by the difference equation y[n+1]+ 0.3 y[n] 0.4x[n] Using the Z-transform, determine the system's zero-input response for the initial value of y[0] 1/3. The solution directly in the time domain is not accepted
• Solve this difference equation by hand using the classical method. y[n] – 1.5 y[n-1] – y[n-2] = x[n], with y[0] = 1 and y[-1] = 0, x[n] = (0.5) n u[n-1].
Please solve using the Discrete-Time Fourier Transform: Given a filter described by the difference equation y[n] = x[n] + 2x[n - 1] + x[n - 3] where x[n] is the input signal and y[n] is the output signal. a) Find H[n] the impulse response of the filter. b) Plot the impulse response c) Find the value of H( Ω) for the following values of Ω = 0, pi, pi/2, and pi/4
1. A difference equation is shown below. y(n)- -0.25 y(n-1)+ 0.125 y(n-2)+ x(n)+x(n-1) (a) Find the transfer function H(z) = Y(z)/ X(z) (b) Find Y(z) ifx(n) = (0.4)nu(n) (n=0,1,2,3, ) (c) If x(n) = y(n)-0 for all n < 0, calculate the values of y(0), y(1) and y(2) directly from the difference equation.
The difference equation y(n+2) -3y(n+1)+2y(n) = 1 for n 20 has initial conditions y(0)= -1 and y(1) 1 1. Find the value of y(3) using iteration. (a) Find the particular solution of y(n) (b) Find Y(z). (It should only be expressed as the ratio of two polynomials) (c) The difference equation y(n+2) -3y(n+1)+2y(n) = 1 for n 20 has initial conditions y(0)= -1 and y(1) 1 1. Find the value of y(3) using iteration. (a) Find the particular solution of...
A LTI system has the following difference equation: y(n)−0.2 y(n−1)+0.8 y(n−2)=2.2333 x(n)+ 2.5 x(n−1)+2.3333 x(n−2). As far as the stability is concerned, choose the right answer from the following list to identify system stability. A LTI system has the following difference equation: y(n)-0.2 y(n-1)+0.8 y(n-2)-2.2333 x(n)+ 2.5 x(n-1)+2.3333 x(n-2) As far as the stability is concerned, choose the right answer from the following list to identify system stability. A. Stable B. Marginally stable C.Unstable D. None
1. The difference equation for a single stage RC circuit, when the input is 1v., is shown below (see Lab 4): y(n) = (y(n-1) + a * Ts) / (1 + a * Ts) (0 < t < 1) where a = 1 / (RC) Ignore the difference equation for the case t > 1, when the input is 0v. (a) Find the Z-transform of y(n) analytically, assuming a time constant of a = 5 and sampling interval of Ts...