Consider the following time series data: Month 1 2 3 4 5 6 7 Value 24 13 21 14 20 23 15 (c) Use α = 0.2 to compute the exponential smoothing values for the time series. Compute MSE and a forecast for month 8. If required, round your answers to two decimal places. Do not round intermediate calculation. MSE: The forecast for month 8: (e) Use trial and error to find a value of the exponential smoothing coefficient α that results in the smallest MSE. If required, round your answer to two decimal places. α =
Answer c: Exponential forecast, alpha 0.2
Month | Demand, At | Forecast, Ft | Absolute deviation= |Forecast - Actual| | squared deviation= (absolute deviation)^2 |
1 | 24 | 24.0 | ||
2 | 13 | 24.00 | 11.0 | 121.0 |
3 | 21 | 21.80 | 0.8 | 0.6 |
4 | 14 | 21.64 | 7.6 | 58.4 |
5 | 20 | 20.11 | 0.1 | 0.0 |
6 | 23 | 20.09 | 2.9 | 8.5 |
7 | 15 | 20.67 | 5.7 | 32.2 |
8 | 19.54 | |||
36.78 | ||||
MSE |
Ft+1= alpha*At + (1-alpha) Ft
At means Actual demand of t'th period, if you want to find out the Forecast through exponential smoothing= forecast of 3rd period = alpha*actual demand of 2nd period +(1-alpha) *forecast demand of 2nd period
Answer e: Trial and error for bet alpha
Fore alpha= 0.4
Month | Demand, At | Forecast, Ft | Absolute deviation= |Forecast - Actual| | squared deviation= (absolute deviation)^2 |
1 | 24 | 24.0 | ||
2 | 13 | 24.00 | 11.0 | 121.0 |
3 | 21 | 19.60 | 1.4 | 2.0 |
4 | 14 | 20.16 | 6.2 | 37.9 |
5 | 20 | 17.70 | 2.3 | 5.3 |
6 | 23 | 18.62 | 4.4 | 19.2 |
7 | 15 | 20.37 | 5.4 | 28.8 |
8 | 18.22 | |||
35.71 | ||||
MSE |
Fore alpha= 0.6
Month | Demand, At | Forecast, Ft | Absolute deviation= |Forecast - Actual| | squared deviation= (absolute deviation)^2 |
1 | 24 | 24.0 | ||
2 | 13 | 24.00 | 11.0 | 121.0 |
3 | 21 | 17.40 | 3.6 | 13.0 |
4 | 14 | 19.56 | 5.6 | 30.9 |
5 | 20 | 16.22 | 3.8 | 14.3 |
6 | 23 | 18.49 | 4.5 | 20.3 |
7 | 15 | 21.20 | 6.2 | 38.4 |
8 | 17.48 | |||
39.64 | ||||
MSE |
For alpha = 0.8
Month | Demand, At | Forecast, Ft | Absolute deviation= |Forecast - Actual| | squared deviation= (absolute deviation)^2 |
1 | 24 | 24.0 | ||
2 | 13 | 24.00 | 11.0 | 121.0 |
3 | 21 | 15.20 | 5.8 | 33.6 |
4 | 14 | 19.84 | 5.8 | 34.1 |
5 | 20 | 15.17 | 4.8 | 23.3 |
6 | 23 | 19.03 | 4.0 | 15.7 |
7 | 15 | 22.21 | 7.2 | 51.9 |
8 | 16.44 | |||
46.63 | ||||
MSE |
For alpha= 0.3
Month | Demand, At | Forecast, Ft | Absolute deviation= |Forecast - Actual| | squared deviation= (absolute deviation)^2 |
1 | 24 | 24.0 | ||
2 | 13 | 24.00 | 11.0 | 121.0 |
3 | 21 | 20.70 | 0.3 | 0.1 |
4 | 14 | 20.79 | 6.8 | 46.1 |
5 | 20 | 18.75 | 1.2 | 1.6 |
6 | 23 | 19.13 | 3.9 | 15.0 |
7 | 15 | 20.29 | 5.3 | 28.0 |
8 | 18.70 | |||
35.29 | ||||
MSE |
Alpha= 0.3 is the best as it gives the least value of MSE
Please ask, if you have any doubts through the comment section. Do rate the answer
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