Cellphone sales person wishes to find the 99% confidence interval estimate for the true number of...
Homework Answers
Solution :
Given that,
= 0.5 ( assume 0.5)
1 -
= 1 - 0.5 = 0.5
margin of error = E = 5% = 0.05
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2
= 0.005
Z/2
= 2.58 ( Using z table )
Sample size = n = (Z
/2
/ E)2 *
* (1 -
)
= (2.58 / 0.05)2 * 0.5 * 0.5
=665.64
Sample size =666
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