A silicon monoxide thin film (n = 1.45) of thickness 83.2 nm is applied to a camera lens made of glass (n = 1.55). This will result in destructive interference for reflected light of what wavelength?
483 nm |
386 nm |
350 nm |
603 nm |
643 nm |
Given
Refractive index of silicon monoxide μs = 1.45
Refractive index of glass μg = 1.55
Thickness of the film t = 83.2 nm
Solution
Here one light wave is reflected at the surface of the silicon dioxide top
One will go through this and then get get reflected by the glass and go through the refraction once again.
To give us the destructive interference the path difference must be λ/2
2μst = λ/2
2 x 1.45 x 83.2 x 10-9 = λ/2
λ = 482.56 x 10-9 m
λ = 483 nm
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