A hard disk has average seek time 9ms, 7200 revolutions per
minute, disk transfer rate
of 30 MBytes/sec and controller transfer rate of 500 MBits/sec.
What is the average
time to read or write a 1KB sector to this hard disk?
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Disk latency = Seek Time + Rotation Time + Transfer Time + Controller Overhead Seek Time? Depends no. tracks the arm moves and seek speed of disk Rotation Time? depends on rotational speed and how far the sector is from the head Transfer Time? depends on data rate (bandwidth) of disk (bit density) and the size of request Disk latency = Seek Time + Rotation Time + Transfer Time + Controller Overhead Average Rotational Time = (0.5)/(7200/60) = 4.166 miliseconds [On average half rotation is made] So Avg. Seek Time = 9 miliseconds. Transfer Time = 1000/ (30 × 106 bytes/sec) = 33.33 microseconds Controller Overhead = 500*125000/(30 × 106 bytes/sec) = 0.208 miliseconds Disk latency = Seek Time + Rotation Time + Transfer Time + Controller Overhead = 9 + 4.166 + 30.33 * 10-3 + 0.2 miliseconds = 13.4 miliseconds
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